S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…

S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…

Question 791. Custom Sort String Solution 题目大意:给你字符的顺序,让你排序另一个字符串. 思路: 输入参数如下: S = "cba" T = "abcd" 先构造一个map,sMap key存储S中出现的字符,value存储字符在S中的位置 c -> 0 b -> 1 a -> 2 再构造一个int数组,sIdx sIdx,存储S中的字符在T字符串中出现的次数 遍历T字符串 如果字符在sMap中,sIdx…

 Arrays.sort(a) 自定义排序,(需实现接口:Comparable) package com.hd; import java.util.Arrays; class Person implements Comparable{ int id ; int score ; public Person(int id,int score){ this.id = id; this.score = score ; } @Override public String toString(){ retur…

S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 按顺序构造字符串 排序 日期 题目地址:https://leetcode.com/problems/custom-sort-string/description/ 题目描述 S and T are strings composed of lowercase letters. In S, no letter occurs more than once.…

S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if x occ…

题目链接:https://leetcode.com/problems/custom-sort-string/description/ S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that…

［抄题］: S and T are strings composed of lowercase letters. In S, no letter occurs more than once. S was sorted in some custom order previously. We want to permute the characters of T so that they match the order that S was sorted. More specifically, if…

Special binary strings are binary strings with the following two properties: The number of 0's is equal to the number of 1's. Every prefix of the binary string has at least as many 1's as 0's. Given a special string S, a move consists of choosing two…