Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns: 1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns: w(20, 20, 20) if a &…

题目传送门:http://poj.org/problem?id=1579 Function Run Fun Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 20560   Accepted: 10325 Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <=…

洛谷P1464 Function HDU P1579 Function Run Fun 题目描述 对于一个递归函数w(a,b,c) 如果a≤0 or b≤0 or c≤0就返回值11. 如果a>20 or b>20 or c>20 就返回w(20,20,20 如果a<b并且b<c 就返回w(a,b,c-1)+w(a,b-1,c-1)-w(a,b-1,c) 其它的情况就返回w(a-1,b,c)+w(a-1,b-1,c)+w(a-1,b,c-1)-w(a-1,b-1,c-1) 这…

Problem Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:w(20, 20, 20)…

Problem Description We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:w(20, 20, 20)…

版权声明:本文为博主原创文章.未经博主同意不得转载.vasttian https://blog.csdn.net/u012860063/article/details/37076755 转载请注明出处:http://blog.csdn.net/u012860063?viewmode=contents 题目链接:pid=1579" rel="nofollow">http://acm.hdu.edu.cn/showproblem.php? pid=1579 Problem…

Description We all love recursion! Don't we?        Consider a three-parameter recursive function w(a, b, c):        if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns:        1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns:…

We all love recursion! Don't we? Consider a three-parameter recursive function w(a, b, c): if a <= 0 or b <= 0 or c <= 0, then w(a, b, c) returns: 1 if a > 20 or b > 20 or c > 20, then w(a, b, c) returns: w(20, 20, 20) if a < b and b…

简单动态规划,详细代码网上有!…

题目链接:http://poj.org/problem?id=1579 思路分析:题目给出递归公式,使用动态规划的记忆搜索即可解决. 代码如下: #include <stdio.h> #include <string.h> + ; int dp[MAX_N][MAX_N][MAX_N]; int w( int a, int b, int c ) { ) return dp[a][b][c]; || b <= || c <= ) ; else if ( a < b…