Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4671   Accepted: 2471 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can affo…

题意: 每个点都可以走多次的TSP问题:有n个点(n<=11),从点1出发,经过其他所有点至少1次,并回到原点1,使得路程最短是多少? 思路: 同HDU 5418 VICTOR AND WORLD (可重复走的TSP问题,状压DP)这道题几乎一模一样. //#include <bits/stdc++.h> #include <iostream> #include <cstdio> #include <cstring> #include <cmat…

题目链接:http://poj.org/problem?id=3311 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can afford to hire only one driver to do the deliveries. He will wait fo…

链接:http://poj.org/problem?id=3311 题意:有N个地点和一个出发点(N<=10),给出全部地点两两之间的距离,问从出发点出发,走遍全部地点再回到出发点的最短距离是多少. 思路:首先用floyd找到全部点之间的最短路.然后用状态压缩,dp数组一定是二维的,假设是一维的话不能保证dp[i]->dp[j]一定是最短的.由于dp[i]记录的"当前位置"不一定是能使dp[j]最小的当前位置.所以dp[i][j]中,i表示的二进制下的当前已经经过的状态,j…

Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can afford to hire only one driver to do the deliveries. He will wait for 1 or more (up to 10) orders to be…

这道题就是Tsp问题,稍微加了些改变 注意以下问题 (1)每个点可以经过多次,这里就可以用弗洛伊德初始化最短距离 (2)在循环中集合可以用S表示更清晰一些 (3)第一维为状态,第二维为在哪个点,不要写混. (4)在dp过程中0这个点是不用的,只用到1到n这个点 而实际上dp过程中用的是0到n-1,所以就枚举1到n,然后涉及到集合的地方就写i-1 其他地方如dp的第二维,距离这些都不变. 还有一个方法,是我一开始想的方法,就是在输入的时候就把0放到第n个点,其他下标-1 (4)这道题求最小值,一定…

题目链接:http://poj.org/problem?id=3311 Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions:12225   Accepted: 6441 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortuna…

floyd,旅游问题每个点都要到,可重复,最后回来,dp http://poj.org/problem?id=3311 Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 4013   Accepted: 2132 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fas…

Hie with the Pie Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 11243   Accepted: 5963 Description The Pizazz Pizzeria prides itself in delivering pizzas to its customers as fast as possible. Unfortunately, due to cutbacks, they can aff…

dp[i][j][k] i代表此层用的状态序号 j上一层用的状态序号 k是层数&1(滚动数组) 标准流程 先预处理出所有合法数据存在status里 然后独立处理第一层 然后根据前一层的max推下一层 由于最多只有60多种状态 所以这其实就是个大暴力 其实还不慢 关于为什么要反义输入地图 因为我懒得写一个地图匹配状态函数了 所以直接让地图反义匹配状态 应该算是比较简单的状压DP 然而我还是写残了WA了两次orz #include <iostream> #include <strin…