Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", => "/c" 解题思路: 首先要了解linux目录的意思,请参考Linux的文件管理 先把path按" /" split,建立一个栈,如果出…
Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" Corner Cases: Did you consider the case where path = "/../"?In th…
Given an absolute path for a file (Unix-style), simplify it. For example,path = "/home/", => "/home"path = "/a/./b/../../c/", => "/c" 使用一个栈来解决问题.遇到'..'弹栈,遇到'.'不操作,其他情况下压栈. 代码一: class Solution: # @param path, a…
题目简述: Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", => "/c" click to show corner cases. 解题思路: 很明显是压栈弹栈的过程,难点在特殊情况要考虑周全,corner c…
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path. Note: You can only move either down or right at any point in time. 解题思路: dp问题,和上一题一样,JAVA实现如下: stati…
主要看//之间的内容:如果是仍是/,或者是.,则忽略:如果是..,则弹出:否则压入堆栈.最后根据堆栈的内容进行输出. string simplifyPath(string const& path) { vector<string> dirs; for (auto i = path.begin(); i != path.end();) { i++; auto j = find(i, path.end(), '/'); auto dir = string(i, j);//注意用法 if (…
leetcode面试准备:Simplify Path 1 题目 Given an absolute path for a file (Unix-style), simplify it. For example, path = "/home/", => "/home" path = "/a/./b/../../c/", => "/c" Corner Cases: Did you consider the case w…