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B是一个看起来很KDT的题  但是因为KDT是n^1.5的所以t  而且因为KDT需要周期性的重建所以复杂度会更高 因为只有51种颜色 所以想当然的就去想了状态压缩 因为询问的区间范围 x一定是从1开始的 所以可以用cdq分治 用cdq分治去掉时间维度 按x排序 用线段树维护每个区间的状态(压缩颜色) 单点更新和区间查询 因为每次线段树做cdq的一部分之后 我们都要去除影响 但是不能rebuild 1 可以用一个last代表这个区间上一次使用线段树是什么时候 每次更新和查询的时候对他进行更新 2…
Covering Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 187    Accepted Submission(s): 107 Problem Description Bob's school has a big playground, boys and girls always play games here after sch…
CS Course Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description Little A has come to college and majored in Computer and Science. Today he has learne…
CS Course Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 593    Accepted Submission(s): 288 Problem Description Little A has come to college and majored in Computer and Science.Today he has lea…
A Math Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 817    Accepted Submission(s): 344 Problem Description You are given a positive integer n, please count how many positive integers…
Problem Description Bob's school has a big playground, boys and girls always play games here after school. To protect boys and girls from getting hurt when playing happily on the playground, rich boy Bob decided to cover the playground using his carp…
HDU 6188 Duizi and Shunzi 链接:http://acm.hdu.edu.cn/showproblem.php?pid=6188 思路: 签到题,以前写的. 实现代码: #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<cmath> #include<stack> #include<map&g…
2017-08-31 16:48:00 writer:pprp 这个题比较容易,我用的是快速幂 写了一次就过了 题目如下: A Math Problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 0    Accepted Submission(s): 0 Problem Description You are given a po…
2017-08-31 16:19:30 writer:pprp 这道题快要卡死我了,队友已经告诉我思路了,但是做题速度很缓慢,很费力,想必是因为之前 的训练都是面向题解编程的缘故吧,以后不能这样了,另外这几天要学习一下动态规划, 先普及两个小知识点,这个点很简单很简单但是却卡了我很久很久, 现在作为模板记录下来: 1.将二进制数转化为十进制数 //转化为十进制 //test:ok ll twoTen(int a[]) { ll ans = ; ; i < N ; i++) { ans += (…
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