简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; ; char s[maxn],t[maxn],u[maxn]; ]; int main() {…

找出一定没问题的字符(即一连串的额字符x个数能被k整除的),剩下的字符都是可能有问题的. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<map> #include<queue> #include<stack> #include<algorithm> using namespace std; int k;…

题意: 输入两行字符串,输出第一行有而第二行没有的字符(对大小写不敏感且全部以大写输出). AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; string s1,s2; ]; vector<char>ans; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL)…

题目信息 1084. Broken Keyboard (20) 时间限制200 ms 内存限制65536 kB 代码长度限制16000 B On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that…

PAT (Advanced Level) Practice 1035 Password (20 分) 凌宸1642 题目描述: To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (o…

PAT (Advanced Level) Practice 1008 Elevator (20 分) 凌宸1642 题目描述: The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order.…

题目 On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen.Now given a string that you are supposed to type, and the string that you actually type out,…

On a broken keyboard, some of the keys are worn out. So when you type some sentences, the characters corresponding to those keys will not appear on screen. Now given a string that you are supposed to type, and the string that you actually type out, p…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

没什么难的,简单模拟题 #include <iostream> using namespace std; int main() { int num; cin>>num; int cost = 0; int curFloor = 0; while (num--) { int floor; cin>>floor; int tmp = floor - curFloor; cost += tmp > 0 ? 6 * tmp : -4 * tmp; cost += 5; c…