problem 720. Longest Word in Dictionary 题意: solution1: BFS; class Solution { public: string longestWord(vector<string>& words) { string res = ""; unordered_set<string> s(words.begin(), words.end()); queue<string> q; for(aut…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力查找 排序 日期 题目地址:https://leetcode.com/problems/longest-word-in-dictionary/description/ 题目描述 Given a list of strings words representing an English Dictionary, find the longest wo…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

［抄题］: Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smal…

Given a list of strings words representing an English Dictionary, find the longest word in words that can be built one character at a time by other words in words. If there is more than one possible answer, return the longest word with the smallest l…

problem 953. Verifying an Alien Dictionary solution: class Solution { public: bool isAlienSorted(vector<string>& words, string order) { unordered_map<char, int> alien_order; ; i<order.size(); i++) { alien_order[order[i]-'a'] = i; } for(…

problem 687. Longest Univalue Path 参考 1. Leetcode_easy_687. Longest Univalue Path; 2. Grandyang; 完…

problem 674. Longest Continuous Increasing Subsequence solution class Solution { public: int findLengthOfLCIS(vector<int>& nums) { , cnt = , cur = INT_MAX; for(auto num:nums) { if(num>cur) cnt++; ; res = max(res, cnt); cur = num; } return res…

problem 594. Longest Harmonious Subsequence 最长和谐子序列 题意: 可以对数组进行排序,那么实际上只要找出来相差为1的两个数的总共出现个数就是一个和谐子序列的长度了. solution1: 使用hashmap 用 HashMap 来做,先遍历一遍,建立每个数字跟其出现次数之间的映射,然后再遍历每个数字的时候,只需在 HashMap 中查找该数字加1是否存在,存在就更新结果 res. class Solution { public: int findLH…