Perfection Kills

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JavaScript 风格指导（Airbnb版）

JavaScript 风格指导(Airbnb版) 用更合理的方式写 JavaScript 原文翻译自 Airbnb JavaScript Style Guide . 目录类型引用对象数组解构字符串函数箭头函数构造函数模块 Iterators & Generators 属性变量提升比较运算符 & 等号代码块注释空白逗号分号类型转换命名规则存取器事件 jQuery ECMAScript 5 兼容性 ECMAScript 6 编码规范测试性能资…

Airbnb JavaScript Style Guide

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HDOJ 1323 Perfection（简单题）

Problem Description From the article Number Theory in the 1994 Microsoft Encarta: "If a, b, c are integers such that a = bc, a is called a multiple of b or of c, and b or c is called a divisor or factor of a. If c is not 1/-1, b is called a proper di…

(25)Teach girls bravery, not perfection

https://www.ted.com/talks/reshma_saujani_teach_girls_bravery_not_perfection/transcript00:12So a few years ago, I did something really brave, or some would say really stupid. I ran for Congress. 00:23For years, I had existed safely behind the scenes i…

(12)We should aim for perfection — and stop fearing failure

https://www.ted.com/talks/jon_bowers_we_should_aim_for_perfection_and_stop_fearing_failure/transcript 00:12Have you ever heard of typosquatting[ˈtaɪpoʊ]打印错误[sk'wɒtɪŋ]非法擅自占用 ? Well, typosquatting is where companies like Google post advertisements on w…

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题目链接:http://poj.org/problem?id=1528 题目大意:输入一个数n,然后求出约数的和sum,在与这一个数n进行比较,如果sum>n,则输出ABUNDANT,如果sum=n,则输出PERFECT,否则,输出DEFICIENT! 注意1的结果是DEFICIENT,0的结果是END OF OUTPUT! #include <iostream> #include <cstdio> using namespace std; int main () { int…

Kills all phantomjs instances, disregard of their origin python关闭进程

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CF GYM 100703I Endeavor for perfection

题意:有n个学习领域,每个领域有m个课程,学习第i个领域的第j个课程可以获得sij个技能点,在每个领域中选择一个课程,要求获得的n个技能点的最大值减最小值最小,输出符合要求的策略. 解法:尺取法.将课程的技能点按值进行排序,同时要记录每个值对应的领域,用尺取法选择第一段包含全部领域的区间,区间的边界即为最值,然后将左指针逐步右移,直到出现有的领域没有选课,继续右移右指针,直到结束.当右指针已移到最右的时候需要特判,只移动左指针. 代码: #include<stdio.h> #include&l…