UVA 167 R-The Sultan's Successors】的更多相关文章

https://vjudge.net/contest/68264#problem/R The Sultan of Nubia has no children, so she has decided that the country will be split into up to k separate parts on her death and each part will be inherited by whoever performs best at some test. It is po…
题目链接:Uva 167 思路分析:八皇后问题,采用回溯法解决问题. 代码如下: #include <iostream> #include <string.h> using namespace std; ; int A[MAX_N]; int M[MAX_N][MAX_N]; ; int is_safe( int row, int col ) { ; i < row; ++i ) { if ( A[i] == col ) return false; if ( A[i] + i…
The Sultan's Successors Description The Sultan of Nubia has no children, so she has decided that the country will be split into up to k separate parts on her death and each part will be inherited by whoever performs best at some test. It is possible…
UVa 167 题意:八行八列的棋盘每行每列都要有一个皇后,每个对角线上最多放一个皇后,让你放八个,使摆放位置上的数字加起来最大. 参考:https://blog.csdn.net/xiaoxiede_wo/article/details/79973171 #include <iostream> #include <cstring> #include <iomanip> using namespace std; ][]; int ans; ][]; void dfs(i…
the squares thus selected sum to a number at least as high as one already chosen by the Sultan. (For those unfamiliar with the rules of chess, this implies that each row and column of the board contains exactly one queen, and each diagonal contains n…
这道题是典型的八皇后问题,刘汝佳书上有具体的解说. 代码的实现例如以下: #include <stdio.h> #include <string.h> #include <stdlib.h> int vis[100][100];//刚開始wrong的原因就是这里数组开小了,开了[8][8],以为可以.后来看到[cur-i+8]意识到可能数组开小了.改大之后AC. int a[8][8]; int C[10]; int max_,tot; void search_(int…
  题意:八皇后问题的扩展.8*8棋盘上每个格子都有一个整数,要求8个皇后所在格子的数字之后最大 解法一,回溯: 用vis数组记录 列,主对角(y-x), 副对角(y+x) 访问情况 #include<cstdio> #include<cstring> #include<iostream> #include<string> #include<algorithm> using namespace std; ], vis[][], tot = , n…
题目例如以下: The Sultan's Successors  The Sultan of Nubia has no children, so she has decided that thecountry will be split into up to k separate parts on her death andeach part will be inherited by whoever performs best at some test. Itis possible for an…
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B: Uva: 12582 - Wedding of Sultan 给定一个字符串(仅由大写字母构成)一个字母表示一个地点,经过这个点或离开这个点都输出这个地点的字母) 问: 每一个地点经过的次数(维护一个栈就能够了,注意进入起点和离开起点都不算入起点的次数) #include<cstdio> #include<cstring> #include<stack> #include<iostream> #include<algorithm> usin…