Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 27028    Accepted Submission(s): 11408 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 11691    Accepted Submission(s): 5336 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ......…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <=…

题目地址: http://acm.hdu.edu.cn/showproblem.php?pid=1711 AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cmath> #include <cstring> #include <string> #include <vector> #include <list> #in…

HDU 1711 Number Sequence (字符串匹配,KMP算法) Description Given two sequences of numbers : a1, a2, ...... , aN, and b1, b2, ...... , bM (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make aK = b1, aK+1 = b2, ...... , aK+M…

HDU 1711 Number Sequence(数列) Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) [Description] [题目描述] Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N…

传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 42917    Accepted Submission(s): 17715 Problem Description Given two sequences…

题目代号:HDU 1711 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 28288    Accepted Submission(s): 11891 Problem Description Give…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 39408    Accepted Submission(s): 16269 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11606    Accepted Submission(s): 5294 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b…

Number Sequence Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 10571    Accepted Submission(s): 4814 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1],…

我的第一道KMP. 把两个数列分别当成KMP算法中的模式串和目标串,这道题就变成了一个KMP算法模板题. #include<stdio.h> #include<string.h> #define N 1000005 #define M 10005 int a[N],b[M]; int next[M]; int n,m; void setNext() { int i,j; i=0; j=-1; next[i]=j; while(i<m) { if(j==-1||b[i]==b[…

Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1]…

http://acm.hdu.edu.cn/showproblem.php?pid=1711 这道题就是一个KMP模板. #include<iostream> #include<cstring> using namespace std; +; int n,m; int next[maxn]; int a[maxn], b[maxn]; void get_next() { , j = ; ::next[] = -; while (j < m) { || b[i] == b[j]…

题目链接 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M…

题意:裸kmp 思路:kmp模板 #include<iostream> #include<stdio.h> #include<string.h> using namespace std; #define MaxSize 10005 ],t[]; int next2[MaxSize]; void GetNext(int t[],int len){//求next数组 int j,k;//,len; j=; k=-; next2[]=-; //len=strlen(t); w…

白书说这个是MP,没有对f 数组优化过,所以说KMP有点不准确 #include <stdio.h> int a,b; int T[1000010],P[10010];//从0开始存 int f[10010];//记录P的自我匹配 void getFail(){ int m=b; f[0]=f[1]=0; for(int i=1;i<m;i++){ int j=f[i]; while(j&&P[i]!=P[j])j=f[j]; f[i+1]= P[i]==P[j] ? j…

这个就是kmp的数组形式,不用来处理字符串还真有点不习惯呢... #include<iostream> using namespace std; ,MAXM = ; int T[MAXN],P[MAXM],Next[MAXM]; void MakeNext(int M) { Next[] = -; , j = -; while(i<M) { ||P[i]==P[j]) { i++,j++; if(P[i]!=P[j])Next[i] = j; else Next[i] = Next[j]…

  Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1] = b[M]. If there a…

题意: 在一个序列中找到一个连续的子序列,返回其开始位置. 思路: 每个数字当成1个字符,长的序列是原串,短的序列是模式串,求next数组后进行匹配. #include <iostream> #include <cmath> #include <cstdio> using namespace std; ; int a[N]; ]; ]; int n, m; void get_next() { nextt[]=-; , j=-; while(i<m) { || b[…

Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 30893    Accepted Submission(s): 12981 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1711 题目意思:给出一条有n个数的序列a[1],a[2],......,a[n],和一条有m 个数的序列b[1],b[2],......,b[m],求出b[1],b[2],...,b[m]在序列a中完全匹配时,在序列a中的位置,如果找不到输出-1. 这几天一直在学kmp,该题算是kmp的入门题吧.有个地方要稍稍注意,代码中,主串和模式串的比较初始值为-1,-1,否则如果从0开始,会默认第一个字符是相…

Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1]…

Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M - 1]…

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题目传送门 /* Rabin_Karp:虽说用KMP更好,但是RK算法好理解.简单说一下RK算法的原理:首先把模式串的哈希值算出来, 在文本串里不断更新模式串的长度的哈希值,若相等,则找到了,否则整个模式串的长度的哈希值向右移动一位 */ /************************************************ * Author :Running_Time * Created Time :2015-8-5 14:04:26 * File Name :HDOJ_1711.…

HDU 1005 Number Sequence(数列) Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) [Description] [题目描述] A number sequence is defined as follows: f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, an…

HDU 1005 Number Sequence(数论) Problem Description: A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7. Given A, B, and n, you are to calculate the value of f(n).   Input The input consists of multipl…

HDU - 1005 Number Sequence Problem Description A number sequence is defined as follows:f(1) = 1, f(2) = 1, f(n) = (A * f(n - 1) + B * f(n - 2)) mod 7.Given A, B, and n, you are to calculate the value of f(n). Input The input consists of multiple test…