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B. Bear and Compressing time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should also kno…
B. Bear and Compressing 题目链接  Problem - B - Codeforces   Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should also know that Limak is so young that he knows only first six letters of the English…
B. Bear and Compressing 题目连接: http://www.codeforces.com/contest/653/problem/B Description Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should also know that Limak is so young that he knows only…
题目链接: B. Bear and Compressing time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. Polar bears hate long strings and thus they like to compress them. You should al…
题目链接: http://codeforces.com/problemset/problem/653/B 题意: 要求你构造一个长度为n的字符串使得通过使用m个操作,最终获得字符a.已知第i个操作将字符串中开头的字符串ai换成字符bi,长度减少1.问一共有多少种字符串构造方法. 分析: 直接dfs一下就好啦~~~ 代码: #include<iostream> #include<algorithm> #include<vector> using namespace std…
F. Bear and Fair Set time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Limak is a grizzly bear. He is big and dreadful. You were chilling in the forest when you suddenly met him. It's very u…
C. Bear and String Distance time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Limak is a little polar bear. He likes nice strings - strings of length n, consisting of lowercase English letter…
Saddest:adj,可悲的,悲哀的,polar,两级的,极地额,YorkShire,约克郡 A UK wildlife park has confirmed that it is offering a new home to a lonely polar bear named Pizza who is living trapped in a chinese mall. 一个英国野生公园报告称他们为名为Pizz的一个孤独的北极熊提供了一个新家,它在中国生活陷入困难. A UK wildlife…
CF 628C 题目大意:给定一个长度为n(n < 10^5)的只含小写字母的字符串,以及一个数d,定义字符的dis--dis(ch1, ch2)为两个字符之差, 两个串的dis为各个位置上字符的dis之和,求和给定的字符串的dis为d的字符串,若含有多个则输出任意一个,不存在输出-1 解题思路:简单贪心,按顺序往后,对每一个字符,将其变为与它dis最大的字符(a或者z),d再减去相应的dis, 一直减到d为0,剩余的字母则不变直接输出.若一直到最后一位d仍然大于0,则说明不存在,输出-1. /…
                                                A. Bear and Elections                                                                                                                                                                            time limi…