Add Two Numbers I You have two numbers represented by a linked list, where each node contains a single digit. The digits are stored in reverse order, such that the 1's digit is at the head of the list. Write a function that adds the two numbers and r…

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

445. 两数相加 II 445. Add Two Numbers II 题目描述 给定两个非空链表来代表两个非负整数.数字最高位位于链表开始位置.它们的每个节点只存储单个数字.将这两数相加会返回一个新的链表. 你可以假设除了数字 0 之外,这两个数字都不会以零开头. 进阶: 如果输入链表不能修改该如何处理?换句话说,你不能对列表中的节点进行翻转. LeetCode445. Add Two Numbers II中等 示例: 输入: (7 -> 2 -> 4 -> 3) + (5 ->…

Question 445. Add Two Numbers II Solution 题目大意:两个列表相加 思路:构造两个栈,两个列表的数依次入栈,再出栈的时候计算其和作为返回链表的一个节点 Java实现: public ListNode addTwoNumbers(ListNode l1, ListNode l2) { Stack<Integer> s1 = new Stack<>(); Stack<Integer> s2 = new Stack<>();…

You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…

原题链接在这里:https://leetcode.com/problems/add-two-numbers-ii/ 题目: You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return…

题目描述: 解题思路: 给定两个链表(代表两个非负数),数字的各位以正序存储,将两个代表数字的链表想加获得一个新的链表(代表两数之和). 如(7->2->4->3)(7243) + (5->6->4)(564) = (7->8->0->7)(7807) 此题与[LeetCode2]Add Two Numbers解决思路类似,不同之处在于此题的数字以正序存储,故需要借助栈. Java代码: import java.util.Stack; //public cl…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 先求和再构成列表 使用栈保存节点数字 类似题目 日期 题目地址:https://leetcode.com/problems/add-two-numbers-ii/description/ 题目描述 You are given two non-empty linked lists representing two non-negative intege…

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. Input: (2 -> 4 -> 3) + (5 -> 6 ->…

反向存储,从左往右加 ［抄题］: 你有两个用链表代表的整数,其中每个节点包含一个数字.数字存储按照在原来整数中相反的顺序,使得第一个数字位于链表的开头.写出一个函数将两个整数相加,用链表形式返回和.给出两个链表 3->1->5->null 和 5->9->2->null,返回 8->0->8->null [暴力解法]: 时间分析: 空间分析: ［思维问题］: 直接从左往右加就行,没看出来. 链表结构改变时要添加dummy,返回的是dummy.next…