考虑dp[i]代表前缀s[1...i]出现的次数,必定有dp[nxt[i]] += dp[i] 倒着推就是了 #include <iostream> #include <cstring> #include <cstdio> using namespace std; int T, n, nxt[200005], dp[200005], ans; const int mod=10007; char a[200005]; void mknxt(){ int k=0; for(…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 3351    Accepted Submission(s): 1564 Problem Description It is well known that AekdyCoin is good at string problems as well as n…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 8845    Accepted Submission(s): 4104 Problem Description It is well known that AekdyCoin is good at string problems as well as n…

D - Count the string Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can wr…

Count the string Problem Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:s: "abab"The prefi…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3637    Accepted Submission(s): 1689 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6062    Accepted Submission(s): 2810 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 14096    Accepted Submission(s): 6462 Problem Description It is well known that AekdyCoin is good at string problems as well as…

http://acm.hdu.edu.cn/showproblem.php?pid=3336 Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 6672    Accepted Submission(s): 3089 Problem Description It is well known that Aek…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 4105    Accepted Submission(s): 1904 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3797    Accepted Submission(s): 1776 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…

题目链接:https://vjudge.net/problem/HDU-3336 Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11760    Accepted Submission(s): 5479 Problem Description It is well known that AekdyCoi…

Count New String 题意: 定义字符串函数 \(f(S,x,y)(1\le x\le y\le n)\),返回一个长度为y-x+1的字符串,第 i 位是 \(max_{i=x...x+k-1}S_i\) 设集合\(A = {f(f(S, x_1,y_1),x_2-x_1+1,y_2-x_1+1)|1\le x_1 \le x_2 \le y_2 \le y_2 \le n}\) 求集合A 的大小 \(N\le 1e5\) 字符集大小 <=10 分析: 先放出官方题解 方法一 核心点…

KMP算法的综合练习 DP很久没写搞了半天才明白.本题结合Next[]的意义以及动态规划考察对KMP算法的掌握. Problem Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this str…

居然一A了,说明对朴素的KMP还是有一定理解. 主要就是要知道next数组的作用,然后就可以计算每个i结尾的满足题意的串个数. #include<cstdio> #include<cstdlib> #include<iostream> #include<cstring> #include<string> #include<algorithm> #include<memory.h> using namespace std;…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:s: "abab"The prefixes are: "a", "ab"…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:  s: "abab"  The prefixes are: "a", "ab&…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example: s: "abab" The prefixes are: "a", "ab&qu…

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 11607    Accepted Submission(s): 5413Problem Description It is well known that AekdyCoin is good at string problems as well as number theory probl…

A website domain like "discuss.leetcode.com" consists of various subdomains. At the top level, we have "com", at the next level, we have "leetcode.com", and at the lowest level, "discuss.leetcode.com". When we visit…

Problem Description It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example: s: "abab" The prefixes are: "…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example: s: "abab" The prefixes are: "a", "ab&qu…

http://acm.hdu.edu.cn/showproblem.php?pid=3336 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 10917    Accepted Submission(s): 5083 Problem Description It is well known that AekdyCoin is good a…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example:s: "abab"The prefixes are: "a", "ab"…

It is well known that AekdyCoin is good at string problems as well as number theory problems. When given a string s, we can write down all the non-empty prefixes of this string. For example: s: "abab" The prefixes are: "a", "ab&qu…

一道字符串匹配的题目,仅仅借此题练习一下KMP 因为这道题目就是要求用从头开始的n个字符串去匹配原来的字符串,很明显与KMP中求next的过程很相似,所以只要把能够从头开始匹配一定个数的字符串的个数加起来就OK了(再此结果上还应该加上字符串的长度,因为每个从头开始的字符串本身也可以去匹配自己的),即将next中值不为-1和0的个数统计出来即可. 用GCC编译的,时间用了46MS. #include <stdio.h> #include <string.h> #define MAXL…

参考连接: KMP+DP: http://www.cnblogs.com/yuelingzhi/archive/2011/08/03/2126346.html 另外给出一个没用dp做的:http://blog.sina.com.cn/s/blog_82061db90100usxw.html 题意: 给出一个字符串,求它的各个前缀在字符串中出现的次数总和. 思路:记 dp[i] 为前 i 个字符组成的前缀出现的次数则 dp[next[i]]+=dp[i] dp[i]表示长度为i的前缀出现的次数,初…

题目 以下不是KMP算法—— 以下是kiki告诉我的方法,好厉害的思维—— 就是巧用标记,先标记第一个出现的所有位置,然后一遍遍从标记的位置往下找. #include<stdio.h> #include<string.h> #include<algorithm> using namespace std; int main() { ],shunxu; ]; scanf("%d",&t); while(t--) { memset(xiabiao,…

题意: 求给定字符串,包含的其前缀的数量. 分析: 就是求所有前缀在字符串出现的次数的和,可以用KMP的性质,以j结尾的串包含的串的数量,就是next[j]结尾串包含前缀的数量再加上自身是前缀,dp[i]表示以i为结尾包含前缀的数量,则dp[i]=dp[next[i]]+1,最后求和即可. #include <map> #include <set> #include <list> #include <cmath> #include <queue>…

题目大意:给你一个串求出来这个串所有的前缀串并且与前缀串相等的数量,比如: ababa 前缀串{"a", "ab", "aba", "abab", "ababa"}: 每个前缀串出现的次数{3, 2, 2, 1, 1},那么结果就是 9.   分析:我们可以用dp[i],表示前i长度的串的结果,那么就可以得到下面的转移方程 dp[i] = dp[next[i]] + 1. 代码如下. ===========…