Codeforces A. Playlist(暴力剪枝)】的更多相关文章

题目:  http://poj.org/problem?id=3714 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=27048#problem/D Raid Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 7355   Accepted: 2185 Description After successive failures in the battles aga…
题目描述: Playlist time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output You have a playlist consisting of n songs. The -th song is characterized by two numbers *t**i* - its length and beauty respec…
You have been given n distinct integers a1, a2, ..., an. You can remove at most k of them. Find the minimum modular m (m > 0), so that for every pair of the remaining integers (ai, aj), the following unequality holds: . Input The first line contains…
题意及思路:https://www.cnblogs.com/Als123/p/11061147.html 代码: #include <bits/stdc++.h> #define LL long long #define INF 0x3f3f3f3f #define db double #define pii pair<int, int> using namespace std; const LL mod = 1e9 + 7; LL mul(LL x, LL y) { return…
Chladni Figure CodeForces - 1162D Inaka has a disc, the circumference of which is nn units. The circumference is equally divided by nn points numbered clockwise from 11 to nn, such that points ii and i+1i+1 (1≤i<n1≤i<n) are adjacent, and so are poin…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5839 在一个三维坐标,给你n个点,问你有多少个四面体(4个点,6条边) 且满足至少四边相等 其余两边不相邻. 暴力4重循环,但是在第3重循环的时候需要判断是否是等腰三角形,这便是一个剪枝.在第4重循环的时候判断4点是否共面 (叉乘), 5或者6边相等就+1,4边相等就判断另外两边是否相交就行了. 赛后过的,觉得自己还是太菜了. //#pragma comment(linker, "/STACK:10…
HDU 4876 ZCC loves cards 题目链接 题意:给定一些卡片,每一个卡片上有数字,如今选k个卡片,绕成一个环,每次能够再这个环上连续选1 - k张卡片,得到他们的异或和的数,给定一个L,问能组成[L,R]全部数字的情况下,R的最大值是多少 思路:暴力C(20, 6),然后对于每一个序列去全排后模拟计算值, 只是之前要有个剪枝.全排前.先把k个数随机取数(即不用连续),然后假设这样还满足不了,那么连续的情况肯定也满足不了.直接结束.不进入全排.这样一来因为满足不了的情况实际上是占…
小晴天老师系列——晴天的后花园 Time Limit: 10000/5000MS (Java/Others)    Memory Limit: 128000/64000KB (Java/Others)   Problem Description 小晴天非常漂亮的后花园,打算以后退休之后在里面种种花,养养草,所以现在小晴天打算为他的后花园围上栅栏. 小晴天的后花园可以看成是一个m*n的矩形,但是其中有一些地方种了树,这些地方都不能安装栅栏,现在小晴天把后花园的平面图告诉你了,请你帮忙设计一个最大的…
odds Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 250    Accepted Submission(s): 72 Problem Description 度度熊有一棵 N 个节点 (node) 的有根树 (rooted tree),树上的每条边 (edge) 都有一个整数的权重,对于每一个非叶的节点 (non-leaf n…
On the way to school, Karen became fixated on the puzzle game on her phone! The game is played as follows. In each level, you have a grid with n rows and mcolumns. Each cell originally contains the number 0. One move consists of choosing one row or c…