Given the coordinates of four points in 2D space, return whether the four points could construct a square. The coordinate (x,y) of a point is represented by an integer array with two integers. Example: Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 =…

Given the coordinates of four points in 2D space, return whether the four points could construct a square. The coordinate (x,y) of a point is represented by an integer array with two integers. Example: Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 =…

LeetCode 题解 593. Valid Square (Medium) 判断给定的四个点,是否可以组成一个正方形 https://leetcode.com/problems/valid-square/solution/ bug "use strict"; /** * * @author xgqfrms * @license MIT * @copyright xgqfrms * @created 2020-11-11 * @modified * * @description 593…

[LeetCode]593. Valid Square 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/valid-square/description/ 题目描述: Given the coordinates of four points in 2D space, return whether the four points could…

Problem statement: Given the coordinates of four points in 2D space, return whether the four points could construct a square. The coordinate (x,y) of a point is represented by an integer array with two integers. Example: Input: p1 = [0,0], p2 = [1,1]…

Given the coordinates of four points in 2D space, return whether the four points could construct a square. The coordinate (x,y) of a point is represented by an integer array with two integers. Example: Input: p1 = [0,0], p2 = [1,1], p3 = [1,0], p4 =…

Given a 2D binary matrix filled with 0's and 1's, find the largest square containing only 1's and return its area. Example: Input: 1 0 1 0 0 1 0 1 1 1 1 1 0 0 1 0 Output: 4 在一个由 0 和 1 组成的二维矩阵内,找到只包含 1 的最大正方形,并返回其面积. 示例: 输入: 1 0 1 0 0 1 0 1 1 1 1 1 1…

实现多态的三个条件:1.要有继承2.要有抽象方法重写3.用父类指针(引用)指向子类对象 重载重写重定义的区别: 1.重载:在同一个类中进行; 编译时根据参数类型和个数决定方法调用; 子类无法重载父类; 父类同名方法被子类该方法覆盖. 2.重写:在父类和子类之间进行; 父类与子类方法有完全相同类型; 在运行时根据具体对象类型决定方法调用; 3.在重写中有抽象方法的会产生多态;没有使用抽象方法叫重定义 以下具体代码具体分析: package test3;abstract class Shape{ /…

［抄题］: 在一个二维01矩阵中找到全为1的最大正方形 1 0 1 0 0 1 0 1 1 1 1 1 1 1 1 1 0 0 1 0 返回 4 [暴力解法]: 时间分析: 空间分析:i j 中保留一排,用指针数组来优化空间存储 ［思维问题］: ［一句话思路］: 棋盘类dp也是用扩展,不过是从右下角开始扩展 最大扩展中的最小值,没见过 ［输入量］:空: 正常情况:特大:特小:程序里处理到的特殊情况:异常情况(不合法不合理的输入): ［画图］: ［一刷］: 第0列初始化完成时,j 从1 开始.第一…

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