Ultra-QuickSort Time Limit: 7000MS Memory Limit: 65536K Total Submissions: 70674 Accepted: 26538 Description In this problem, you have to analyze a particular sorting algorithm. The algorithm processes a sequence of n distinct integers by swappin…
题目链接 Sequence II Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 331 Accepted Submission(s): 151 Problem Description Long long ago, there is a sequence A with length n. All numbers in this se…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1394 Minimum Inversion Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 10…
Ping pong Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 3109 Accepted: 1148 Description N(3<=N<=20000) ping pong players live along a west-east street(consider the street as a line segment). Each player has a unique skill rank. To i…
题目链接: 传送门 Minimum Inversion Number Time Limit: 1000MS Memory Limit: 32768 K Description The inversion number of a given number sequence a1, a2, ..., an is the number of pairs (ai, aj) that satisfy i < j and ai > aj. For a given sequence of numbe…
题目链接:http://poj.org/problem?id=2299 求逆序数的经典题,求逆序数可用树状数组,归并排序,线段树求解,本文给出树状数组,归并排序,线段树的解法. 归并排序: #include<cstdio> #include<iostream> using namespace std; #define max 500002 int arr[max],b[max];//b[]为临时序列,arr[]为待排序数列,结果在arr[]中 int tp[max]; ;//总逆序…
