Problem Description Given a string containing only 'A' - 'Z', we could encode it using the following method: Each sub-string containing k same characters should be encoded to "kX" where "X" is the only character in this sub-string. If…

Encoding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 11132    Accepted Submission(s): 4673 Problem Description Given a string containing only 'A' - 'Z', we could encode it using the followin…

Encoding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39047    Accepted Submission(s): 17279 Problem Description Given a string containing only 'A' - 'Z', we could encode it using the followi…

Encoding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 51785    Accepted Submission(s): 23041 Problem Description Given a string containing only 'A' - 'Z', we could encode it using the followi…

Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Description Given a string containing only 'A' - 'Z', we could encode it using the following method: 1. Each sub-string containing k same characters should be encoded to &quo…

pid=1020">Encoding Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 25691    Accepted Submission(s): 11289 Problem Description Given a string containing only 'A' - 'Z', we could encode it usi…

1. string对象的定义和初始化以及读写 string s1; 默认构造函数,s1为空串string s2(s1); 将s2初始化为s1的一个副本string s3("valuee"); 将s3初始化一个字符串面值副本string s4(n,'c'); 将s4 初始化为字符'c'的n个副本cin>>s5; 读取有效字符到遇到空格getline(cin,s6); 读取字符到遇到换行,空格可读入,遇'\n'结束getline(cin,s7,'a'); 遇'a'结束,其中任何…

在学习c++STL中的string,在这里做个笔记,以供自己以后翻阅和初学者参考. 1:string对象的定义和初始化以及读写 string s1;      默认构造函数,s1为空串 string s2(s1);   将s2初始化为s1的一个副本 string s3("valuee");   将s3初始化一个字符串面值副本 string s4(n,'c');   将s4 初始化为字符'c'的n个副本 cin>>s5;  读取有效字符到遇到空格 getline(cin,s6…

本文直接转载,非原创!仅记录供自己学习之用. 出处:http://blog.csdn.net/y990041769/article/details/8763366 在学习c++STL中的string,在这里做个笔记,以供自己以后翻阅和初学者参考. 1:string对象的定义和初始化以及读写 string s1;      默认构造函数,s1为空串 string s2(s1);   将s2初始化为s1的一个副本 string s3("valuee");   将s3初始化一个字符串面值副本…

HDOJ 题目分类 //分类不是绝对的 //"*" 表示好题,需要多次回味 //"?"表示结论是正确的,但还停留在模块阶 段,需要理解,证明. //简单题看到就可以敲的 1000:    入门用: 1001:    用高斯求和公式要防溢出 1004:1012: 1013:    对9取余好了 1017:1021: 1027:    用STL中的next_permutation() 1029:1032:1037:1039:1040:1056:1064:1065: 10…