Given a 2D binary matrix filled with 0's and 1's, find the largest rectangle containing only 1's and return its area. Example: Input: [ ["1","0","1","0","0"], ["1","0","1",&qu…

class Solution { public int maximalRectangle(char[][] matrix) { if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return 0; int[] height = new int[matrix[0].length]; for(int i = 0; i < matrix[0].length; i ++){ if(matrix[0][i] == '1')…

思路: 分别按行拆分后将这一行之前的每列叠加起来,然后使用leetcode84https://www.cnblogs.com/wangyiming/p/9620942.html的思路计算. 实现: #include <bits/stdc++.h> using namespace std; class Solution { public: int maximalRectangle(vector<vector<char>>& matrix) { ) ; ].size…

public static int maximalRectangle(char[][] matrix) { int rowNum=matrix.length; if(rowNum==0) return 0; int columnNum=matrix[0].length; int[][] height=new int[rowNum][columnNum+1]; int maxarea=0; for(int i=0;i<rowNum;i++) { for(int j=0;j<columnNum;j…

思路: 这题应该不止一种解法,其中的一种可以看作是leetcode85https://www.cnblogs.com/wangyiming/p/11059176.html的加强版: 首先对于每一行,分别使用滑动窗口法将这一行划分成符合题目定义的若干合法子段s1, s2, s3, ....对于每一段si,从起点到终点分别将每个元素分别编号为1, 2, 3, ..., |si|. 例如: 2 2 4 4 20 8 3 3 3 12 6 6 3 3 3 1 6 8 6 4 可以转化成 1 2 1 2…