Divide the Sequence】的更多相关文章

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Divide the Sequence 题意: 给你一个序列A,问你最多能够分成多少个连续子序列,使得每个子序列的所有前缀和均不小于0 题解: 这题是比赛时候的水题,但我比的时候也就做出这一题, = = 首先我想的是把他们前缀和求出来,之后试了下样例,一点鸟用都没有,那正着不行就倒着试下呗,之后发现这样有用,我先想到的思路是求后缀和,只要>=0就ans++,但那时队友举出了反例,比如2 1 -3 3的时候应该是2,我的算法就是4,那接着马上就能想到如果后缀和大于0,那么就要把他赋为0,之后举了几…
Divide the Sequence Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 649    Accepted Submission(s): 331 Problem Description Alice has a sequence A, She wants to split A into as much as possible c…
Divide the Sequence 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not smal…
Divide the Sequence 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not smal…
Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequences, satisfying that for each subsequence, every its prefix sum is not small than 0. Input The input consists of multiple test cases. Each test case…
Time Limit: 5000/2500 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2232    Accepted Submission(s): 628 Problem Description Alice has a sequence A, She wants to split A into as much as possible continuous subsequen…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5783 题意:给n个数,要求划分成多个段,使得每一个段的任意前缀和都不小于0. 从后往前截取,这样不会影响到未截取的部分.维护当前的前缀和,每次截取不要忘记给前缀和置零. #include <bits/stdc++.h> using namespace std; typedef long long LL; ; int n, ret; LL cur; LL a[maxn]; int main() {…
题目大意:给一个整数序列,将其划分成若干个子连续序列,使其每个子序列的前缀和不为负.求最大的划分个数. 题目分析:从后往做累加计算,如果不为负,则计数加一,累加和清0.否则,一直往前扫描.如果最终的和为负,答案为0,否则为计数结果. 代码如下: # include<iostream> # include<cstdio> # include<algorithm> using namespace std; # define LL long long const int N=…
题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5783 题目大意: 把一个N个数的数列拆成若干段,保证每一段的前缀和都非负,求最多能拆成多少段. 题目思路: [贪心] 一开始题目看错了看成每一段内和非负..DPWA了好久. 默认答案是n,从后往前找负数,找到一个负数就一直把它往前合并直到和值非负,这样这个区间的前缀和就一定非负,扣除合并的区间大小即可. // //by coolxxx //#include<bits/stdc++.h> #inc…