Highway Project Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities from the capital as fast as possible. Thus, he proposed the highw…

题意:单源最短路,给你一些路,给你这些路的长度,给你修这些路的话费,求最短路和最小花费. 析:本质就是一个最短路,不过要维护两个值罢了,在维护花费时要维护的是该路要花多少,而不是总的路线花费. 代码如下: #pragma comment(linker, "/STACK:1024000000,1024000000") #include <cstdio> #include <string> #include <cstdlib> #include <…

ZOJ Problem Set - 3946 Highway Project Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities from the capital as fast as possible. Thus…

Highway Project Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities from the capital as fast as possible. Thus, he proposed the highw…

题目链接: http://www.icpc.moe/onlinejudge/showProblem.do?problemCode=3946 题解: 用dijkstra跑单元最短路径,如果对于顶点v,存在一系列边(ui,v)使得dis[v]最小(dis[v]表示0到v的距离).这些边能且只能选一条,那么我们自然应该选cost最小的那个边了. #include<iostream> #include<cstdio> #include<cstring> #include<…

1.迪杰斯特拉最小堆 #include<cstdio> #include<cstring> #include<cmath> #include<map> #include<queue> #include<algorithm> using namespace std; ; ; struct X{ int id; long long time,cost; bool operator < (const X &a) const {…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5718   Highway Project Time Limit: 2 Seconds      Memory Limit: 65536 KB Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities…

Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities from the capital as fast as possible. Thus, he proposed the highway project. The Marjar Empire has N cities (including the capital)…

本文转载自:http://www.javaxxz.com/thread-359442-1-1.html Edward, the emperor of the Marjar Empire, wants to build some bidirectional highways so that he can reach other cities from the capital as fast as possible. Thus, he proposed the highway project.The…

题目大意:一张带权无向图,权有两个参数(d,c),分别表示走过这条边的时间和建造这条边的代价.要求选出一些边,使得0节点到其他点的距离之和最短,并在最短的基础上求最小代价. 题目分析:这是16年浙江省赛的一道题.先求出0到所有点的最短路,然后找出所有可能在最短路径上的边,最后在每一个节点的入边之中都选一条具有最小代价的边.多么简单的一道题!!! 代码如下: # include<iostream> # include<cstdio> # include<cstring>…

ROADS Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 13436   Accepted: 4921 Description N cities named with numbers 1 ... N are connected with one-way roads. Each road has two parameters associated with it : the road length and the toll…

/*两个约束条件求最短路,用优先队列*/ #include<stdio.h> #include<string.h> #include<queue> using namespace std; #define N 110 struct node { int u,v,w,f,next; }bian[N*N*4]; int head[N],yong,money; void init() { memset(head,-1,sizeof(head)); yong=0; } stru…

不能用全局数组d[u]>d[rhs.u]. 这样后面会修改d[u]值然而本来里面的点顺序不该修改,却被修改了. 应该用栈还存进去的临时变量,比如d>rhs.d. 优先队列重载小于号'<' struct Node { int u,d,c; bool operator<(const Node &rhs)const { if(d!=rhs.d) return d > rhs.d; return c > rhs.c; } Node(int u_,int d_,int c…

链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=2724 Message queue is the basic fundamental of windows system. For each process, the system maintains a message queue. If something happens to this process, such as mouse click, text cha…

传送门 E. Breaking Good time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Breaking Good is a new video game which a lot of gamers want to have. There is a certain level in the game that is real…

http://acm.zju.edu.cn/onlinejudge/showProblem.do? problemId=655 没有理解清题意就硬套模板.所以WA了好几次. 解析看我的还有一篇http://blog.csdn.net/u011026968/article/details/35579035 贴代码 #include <cstdio> #include <cstring> #include <algorithm> using namespace std; #…

  前4道水题就不说了,其中我做了C题,1Y,小心仔细写代码并且提交之前得确认无误后提交才能减少出错率. 结果后面2题都由波神做掉,学长带我们飞~ 终榜 官方题解   ZOJ 3946 Highway Project(K题) 题意:求到所有点最短花费时间总和以及在这前提下的走过的路的最小花费金钱 分析:首先最短路跑一个,然后在d[v] == d[u] + time的一些边上选择最小金钱,注意这里只要cost[v] = cost不用累加cost[u].就是跑了两次最短路. #include <bi…

A      Apples and Ideas Time Limit: 2 Seconds      Memory Limit: 65536 KB "If you have an apple and I have an apple and we exchange these apples then you and I will still each have one apple. But if you have an idea and I have an idea and we exchange…

[SinGuLaRiTy-1041] Copyright (c) SinGuLaRiTy 2017. All Rights Reserved. 计算树的直径 //方法:任选一个点作为起点进行一次BFS,找到最远点u.再以u为起点做一次BFS,找最长路即直径. queue<int>point; void bfs(int a,int dis[]) { memset(dis,inf,sizeof dis); dis[a]=; point.push(a); int v ,u ; while(!poin…

畅通project续 Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 28578    Accepted Submission(s): 10382 Problem Description 某省自从实行了非常多年的畅通project计划后.最终修建了非常多路. 只是路多了也不好,每次要从一个城镇到还有一个城镇时.都有很多种道路方案能够选择…

再开始前我们先普及一下简单的图论知识 图的保存: 1.邻接矩阵. G[maxn][maxn]; 2.邻接表 邻接表我们有两种方式 (1)vector< Node > G[maxn]; 这个是之前就定义了图的大小了,再下面使用的时候就不用对图的大小进行申请了, 但是因为是直接申请了大小 要对图进行初始化,因此可能在某些题目中这样使用的话会超时 (2)vector< vector<Node> > G; 这个是未定义大小,但是在使用之前要对其的大小内存进行申请. G.resi…

最开始学最短路的时候只会用map二维数组存图,那个时候还不知道这就是矩阵存图,也不懂得效率怎么样 经过几个月的历练再回头看最短路的题, 发现图可以用链式前向星来存, 链式前向星的效率是比较高的.对于查找边,可以用优先队列来优化查找速度,两者结合可以提高很高的效率. 写这篇博客是为了给自己提供一个模板, 在自己研究这问题的时候发生了很多, 有一些小细节的错误错的我怀疑人生, 其实还是自己太菜了,包括函数的重载也不懂, 就琢磨了好久 题目链接:http://acm.hdu.edu.cn/showpr…

题目链接:http://poj.org/problem?id=2449 Time Limit: 4000MS Memory Limit: 65536K Description "Good man never makes girls wait or breaks an appointment!" said the mandarin duck father. Softly touching his little ducks' head, he told them a story. &quo…

题目链接:http://poj.org/problem?id=3635 Description After going through the receipts from your car trip through Europe this summer, you realised that the gas prices varied between the cities you visited. Maybe you could have saved some money if you were…

描述 As head of the Accessible Commuting Movement (ACM), you've been lobbying the mayor to build a new highway in your city. Today is your lucky day, because your request was approved. There is one condition though: You must provide the plan for the be…

K - Watermelon Full of Water Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu Submit Status Practice ZOJ 3632 Appoint description:   Description Watermelon is very popular in the hot summer. Students in ZJU-ICPC Team also lo…

poj1724 ROADS Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10751   Accepted: 3952 Description N cities named with numbers 1 ... N are connected with one-way roads. Each road has two parameters associated with it : the road length and…

Invitation Cards Time Limit: 8000MS   Memory Limit: 262144K Total Submissions: 16178   Accepted: 5262 Description In the age of television, not many people attend theater performances. Antique Comedians of Malidinesia are aware of this fact. They wan…

I. Move Between Numbers   time limit per test 2.0 s memory limit per test 256 MB input standard input output standard output You are given n magical numbers a1, a2, ..., an, such that the length of each of these numbers is 20 digits. You can move fro…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3230 Programming is fun, Aaron is addicted to it. In order to improve his programming skill, he decides to solve one programming problem per day. As you know, different problems have d…