Lintcode: Minimum Subarray 解题报告】的更多相关文章

Minimum Subarray 原题链接: http://lintcode.com/zh-cn/problem/minimum-subarray/# Given an array of integers, find the subarray with smallest sum. Return the sum of the subarray. 注意 The subarray should contain at least one integer. 样例 For [1, -1, -2, 1], r…
[LeetCode]718. Maximum Length of Repeated Subarray 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/maximum-length-of-repeated-subarray/description/ 题目描述: Given two integer arr…
Given an array of integers, find the subarray with smallest sum. Return the sum of the subarray. Have you met this question in a real interview? Yes Example For [1, -1, -2, 1], return -3 Note The subarray should contain at least one integer. public c…
http://fisherlei.blogspot.com/2012/12/leetcode-maximum-subarray.html Find the contiguous subarray within an array (containing at least one number) which has the largest sum. For example, given the array [−2,1,−3,4,−1,2,1,−5,4],the contiguous subarray…
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作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 虫取法 日期 题目地址:https://leetcode.com/problems/longest-turbulent-subarray/ 题目描述 A subarray A[i], A[i+1], ..., A[j] of A is said to be turbulent if and only if: For i <= k < j, A[k]…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 双重循环 动态规划 参考资料 日期 题目地址:https://leetcode.com/problems/maximum-product-subarray/description/ 题目描述 Given an integer array nums, find the contiguous subarray within an array (conta…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 解题方法 方法一:排序比较 日期 题目地址:https://leetcode.com/problems/shortest-unsorted-continuous-subarray/description/ 题目描述 Given an integer array, you need to find one continuous subarray that if you o…
K SUM My Submissions http://www.lintcode.com/en/problem/k-sum/ 题目来自九章算法 13% Accepted Given n distinct positive integers, integer k (k <= n) and a number target. Find k numbers where sum is target. Calculate how many solutions there are? Example Given…