Matrix Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 25004   Accepted: 9261 Description Given an N*N matrix A, whose elements are either 0 or 1. A[i, j] means the number in the i-th row and j-th column. Initially we have A[i, j] = 0 (1…

树状数组(BIT)是一个查询和修改复杂度都为log(n)的数据结构,主要用于查询任意两位之间的所有元素之和,其编程简单,很容易被实现.而且可以很容易地扩展到二维.让我们来看一道很裸的二维树状数组题: 在一个“打鼹鼠”的游戏中,鼹鼠会不时地从洞中钻出来,不过不会从洞口钻进去(鼹鼠真胆大……).洞口都在一个大小为n(n<=1024)的正方形中.这个正方形在一个平面直角坐标系中,左下角为(0,0),右上角为(n-1,n-1).洞口所在的位置都是整点,就是横纵坐标都为整数的点.而SuperBrother…

escription Input Output Sample Input Sample Output 1 2 HINT —————————————————————————————————————————— 这道题是裸的二维树状数组.....直接每个颜色弄一个二维的树状数组然后容斥(也不知道算不算)就可以辣 #include<cstdio> #include<cstring> #include<algorithm> int read(){ ,f=,c=getchar();…

Description "第一分钟,X说,要有矩阵,于是便有了一个里面写满了\(0\)的\(n\times m\)矩阵. 第二分钟,L说,要能修改,于是便有了将左上角为\((a,b)\),右下角为\((c,d)\)的一个矩形区域内的全部数字加上一个值的操作. 第三分钟,k说,要能查询,于是便有了求给定矩形区域内的全部数字和的操作. 第四分钟,彩虹喵说,要基于二叉树的数据结构,于是便有了数据范围. 第五分钟,和雪说,要有耐心,于是便有了时间限制. 第六分钟,吃钢琴男说,要省点事,于是便有了保证运算…

Mobile phones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 14489   Accepted: 6735 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…

Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…

Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…

Mobile phones Time Limit: 5000MS   Memory Limit: 65536K Total Submissions: 16893   Accepted: 7789 Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The…

<题目链接> 题目大意: 一个由数字构成的大矩阵,开始是全0,能进行两种操作1) 对矩阵里的某个数加上一个整数(可正可负)2) 查询某个子矩阵里所有数字的和要求对每次查询,输出结果 解题分析: 二维树状数组模板题,需要注意的是,由于题目给的x,y坐标可以为0,所以我们应该将这些点的坐标全部+1,然后就是查询指定子矩阵中所有元素之和,很直观的就能得到式子 ans=sum(x2,y2)-sum(x1-1,y2)-sum(x2,y1-1)+sum(x1-1,y1-1). #include <c…

Description Suppose that the fourth generation mobile phone base stations in the Tampere area operate as follows. The area is divided into squares. The squares form an S * S matrix with the rows and columns numbered from 0 to S-1. Each square contain…