给定一棵二叉树,返回其节点值的前序遍历.例如:给定二叉树[1,null,2,3], 1 \ 2 / 3返回 [1,2,3].注意: 递归方法很简单,你可以使用迭代方法来解决吗?详见:https://leetcode.com/problems/binary-tree-preorder-traversal/description/ Java实现: 递归实现: /** * Definition for a binary tree node. * public class T…
Given a binary tree, return the preorder traversal of its nodes' values. Example: Input: [,,] \ / Output: [,,] Follow up: Recursive solution is trivial, could you do it iteratively? 方法一:使用迭代(C++) vector<int> preorderTraversal(TreeNode* root) { vecto…
Given an n-ary tree, return the preorder traversal of its nodes' values. For example, given a 3-ary tree: Return its preorder traversal as: [1,3,5,6,2,4]. Note: Recursive solution is trivial, could you do it iteratively? 这道题让我们求N叉树的前序遍历,有之前那道Binary T…
LeetCode:N叉树的前序遍历[589] 题目描述 给定一个 N 叉树,返回其节点值的前序遍历. 例如,给定一个 3叉树 : 返回其前序遍历: [1,3,5,6,2,4]. 题目分析 使用栈结构.处于栈顶的是根元素,然后逆序加入其子元素,这样处于栈顶的就是其左子节点,处于栈低的是其右子节点.然后出栈打印即可. Java题解 /* // Definition for a Node. class Node { public int val; public List<Node> children…
589. N叉树的前序遍历 给定一个 N 叉树,返回其节点值的前序遍历. 例如,给定一个 3叉树 : 返回其前序遍历: [1,3,5,6,2,4]. 说明: 递归法很简单,你可以使用迭代法完成此题吗? /* // Definition for a Node. class Node { public int val; public List<Node> children; public Node() {} public Node(int _val) { val = _val; } public…
问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/4090 访问. 给定一个 N 叉树,返回其节点值的前序遍历. 例如,给定一个 3叉树 : 返回其前序遍历: [1,3,5,6,2,4]. 说明: 递归法很简单,你可以使用迭代法完成此题吗? Given an n-ary tree, return the preorder traversal of its nodes' values. For example, gi…
144. Binary Tree Preorder Traversal Difficulty: Medium Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. Note: Recursive solution is trivial, could you do it it…
[题目] 给定一个 N 叉树,返回其节点值的前序遍历. 例如,给定一个 3叉树 : 返回其前序遍历: [1,3,5,6,2,4]. [解析] """ # Definition for a Node. class Node(object): def __init__(self, val, children): self.val = val self.children = children """ class Solution(object): de…
题目链接 题目大意:返回二叉树的先序遍历list.中序见94,后序见145. 法一:普通递归遍历,只是这里多了一个list数组,所以分成了两个函数.代码如下(耗时1ms): public List<Integer> preorderTraversal(TreeNode root) { List<Integer> list = new ArrayList<Integer>(); list = dfs(root, list); return list; } public s…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 迭代 日期 题目地址:https://leetcode.com/problems/n-ary-tree-preorder-traversal/description/ 题目描述 Given an n-ary tree, return the preorder traversal of its nodes' values. For example,…
Given an n-ary tree, return the preorder traversal of its nodes' values. For example, given a 3-ary tree: Return its preorder traversal as: [1,3,5,6,2,4]. Note: Recursive solution is trivial, could you do it iteratively? -----------------------------…
题目要求 Given an n-ary tree, return the preorder traversal of its nodes' values. 题目分析及思路 题目给出一棵N叉树,要求返回结点值的前序遍历.可以使用递归的方法做.因为是前序遍历,所以最开始就加入根结点的值. python代码 """ # Definition for a Node. class Node: def __init__(self, val, children): self.val = v…
Binary Tree Preorder Traversal Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. Note: Recursive solution is trivial, could you do it iteratively? Solution: 递归…
详见:剑指 Offer 题目汇总索引:第6题 Binary Tree Postorder Traversal Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could…
Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. 二叉树的前序遍历,根节点→左子树→右子树 解题思路一: 递归实现,JAVA实现如下: public List<Integer> preorderTraversal(TreeNode root) { List<I…