成绩转换 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 117938    Accepted Submission(s): 51743 Problem Description 输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下: 90~100为A; 80~89为B; 70~79为C; 60~69为D; 0~59为E; In…

#include<cstdio> #include<iostream> using namespace std; int main() { int score; while (cin >> score) { || score < ) { printf("Score is error!\n"); } ) { printf("A\n"); } ) { printf("B\n"); } ) { printf(&…

成绩转换 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 70452    Accepted Submission(s): 30852 Problem Description 输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下:90~100为A;80~89为B;70~79为C;60~69为D;0~59为E;   Input 输…

成绩转换 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 90024    Accepted Submission(s): 39714 Problem Description 输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下: 90~100为A; 80~89为B; 70~79为C; 60~69为D; 0~59为E; Inp…

/*成绩转换Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 140424    Accepted Submission(s): 61308Problem Description输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下:90~100为A;80~89为B;70~79为C;60~69为D;0~59为E; Input输入数据…

水题:用数组标识各个阶段分数的等级即可. HDOJ2004_成绩转换 #include<stdio.h> #include<stdlib.h> #include<math.h> #include<string.h> int main() { int i,j,n; char sco[101]; for(i=0;i<=59;i++) { sco[i]='E'; } for(i=60;i<=69;i++) { sco[i]='D'; } for(i=7…

成绩转换 Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 173950    Accepted Submission(s): 76178 Problem Description 输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下:90~100为A;80~89为B;70~79为C;60~69为D;0~59为E;   Input…

成绩转换Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 57281    Accepted Submission(s): 24928 Problem Description输入一个百分制的成绩t,将其转换成对应的等级,具体转换规则如下:90~100为A;80~89为B;70~79为C;60~69为D;0~59为E; Input输入数据有多…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=2004 中文题目,简单题. 题意:将分数转换成ABC制 查表法 #include <stdio.h> int main() { int score; char convert[] = "EEEEEEDCBAA"; while(scanf("%d", &score) != EOF) { if(score < 0 || score > 100) p…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=2004 题目大意: 给你成绩让你根据成绩打分解题思路: 简单的if...else 应用 需要注意是,if....else if ....else ..if....不能写成 if...if.....if....else ..... 比如 int q; ; ) q = ; ) q = ; ) q = ; else q = ; 最后会进入到 ) q = ; else q = ; 所以最后输出要么 q 是 3…