目录 题目链接 题解 题目链接 luogu P2962 [USACO09NOV]灯Lights 题解 可以折半搜索 map合并 复杂度 2^(n / 2)*logn 高斯消元后得到每个点的翻转状态 爆搜自由元得到最优翻转状态 // luogu-judger-enable-o2 #include<map> #include<queue> #include<cstdio> #include<cstring> #include<algorithm> u…

题目描述 Bessie and the cows were playing games in the barn, but the power was reset and the lights were all turned off. Help the cows get all the lights back on so they can resume their games. The N (1 <= N <= 35) lights conveniently numbered 1..N and…

luogu 点灯游戏应该很多人都在小时候頽过吧 反正我直到现在也不会 很明显一个灯最多只需要点一次 然后高斯消元 解完肯定剩自由元(就是那些全是0的行) 然后这些都爆搜 由于剩下的自由元不会太多 所以时间复杂度$O(能过)$ 以上 #include<cstdio> #include<algorithm> using std::swap; ; template<typename tp>void read(tp &kk){ tp ret=,f=;char ch=ge…

Description Bessie and the cows were playing games in the barn, but the power was reset and the lights were all turned off. Help the cows get all the lights back on so they can resume their games. The N (1 <= N <= 35) lights conveniently numbered 1.…

贝希和她的闺密们在她们的牛棚中玩游戏.但是天不从人愿,突然,牛棚的电源跳闸了,所有的灯都被关闭了.贝希是一个很胆小的女生,在伸手不见拇指的无尽的黑暗中,她感到惊恐,痛苦与绝望.她希望您能够帮帮她,把所有的灯都给重新开起来!她才能继续快乐地跟她的闺密们继续玩游戏! 牛棚中一共有N(1 <= N <= 35)盏灯,编号为1到N.这些灯被置于一个非常複杂的网络之中.有M(1 <= M <= 595)条很神奇的无向边,每条边连接两盏灯. 每盏灯上面都带有一个开关.当按下某一盏灯的开关的时候…

题目链接 因为这个专门跑去学了矩阵树定理和高斯消元qwq 不过不是很懂.所以这里只放题解 玫葵之蝶的题解 某未知dalao的矩阵树定理 代码 #include<cstdio> #include<cstdlib> #include<cctype> #include<algorithm> #include<cstring> #include<cmath> #define eps 1e-8 #define maxn 100 using na…

大概就是对每一行先找到最大的减小误差,然后代入消元 #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> #include<cmath> #include<algorithm> #include<queue> #include<vector> #include<map> #include<set>…

\(\color{#0066ff}{题目描述}\) 贝希和她的闺密们在她们的牛棚中玩游戏.但是天不从人愿,突然,牛棚的电源跳闸了,所有的灯都被关闭了.贝希是一个很胆小的女生,在伸手不见拇指的无尽的黑暗中,她感到惊恐,痛苦与绝望.她希望您能够帮帮她,把所有的灯都给重新开起来!她才能继续快乐地跟她的闺密们继续玩游戏! 牛棚中一共有N(1 <= N <= 35)盏灯,编号为1到N.这些灯被置于一个非常複杂的网络之中.有M(1 <= M <= 595)条很神奇的无向边,每条边连接两盏灯.…

题目描述 Bessie and the cows were playing games in the barn, but the power was reset and the lights were all turned off. Help the cows get all the lights back on so they can resume their games. The N (1 <= N <= 35) lights conveniently numbered 1..N and…

果然如Miracle学长所说...调了一天...qwq..还是过不了线下的Hack upd after 40min:刚刚过了 就是多了一个判无解的操作... 当系数都为0,且常数项不为0时,即为无解. 当找到自由元时,不能跳过这一行...否则会被Hack,见洛谷讨论 #include<cstdio> #include<iostream> #include<cmath> #define R register int using namespace std; ; inlin…