pku1365 Prime Land （数论，合数分解模板）

【pku1365 Prime Land （数论，合数分解模板）】的更多相关文章

pku1365 Prime Land （数论，合数分解模板）

题意:给你一个个数对a, b 表示ab这样的每个数相乘的一个数n,求n-1的质数因子并且每个指数因子k所对应的次数 h. 先把合数分解模板乖乖放上: ; ans != ; ++i) { ) { num[cnt] = i; ; ){ ++k; ans /= i; } index[cnt++] = k; } )break; } ){ num[cnt] = ans; index[cnt++] = ; } 然后,我自己写了个快速幂快速幂的模板: ll pow(ll a, ll n) { ll res;…

POJ1365 - Prime Land（质因数分解）

题目大意给定一个数的质因子表达式,要求你计算机它的值,并减一,再对这个值进行质因数分解,输出表达式题解预处理一下,线性筛法筛下素数,然后求出值来之后再用筛选出的素数去分解....其实主要就是字符串处理... 代码: #include <stdio.h> #include <string.h> #include <math.h> #define MAXN 10000 ]; ],cnt=; ]; void get_prime() { ; memset(check,fa…

POJ1365 Prime Land【质因数分解】【素数】【水题】

题目链接: http://poj.org/problem?id=1365 题目大意: 告诉你一个数的质因数x的全部底数pi和幂ei.输出x-1的质因数的全部底数和幂解题思路: 这道题不难.可是题意特别不好理解.对于我这样的英文渣的人.愣是一个小时没看明确关于题意举例说明吧比如 509 1 59 1 x = 509^1 * 59^1 = 30031 x-1 = 30030 则答案 13 1 11 1 7 1 5 1 3 1 2 1 就是 x-1 = 13^1 * 11^1 * 7^1 * 5…

HDU 4610 Cards （合数分解，枚举）

Cards Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 470 Accepted Submission(s): 72 Problem Description Given some cards each assigned a number, you're required to select EXACTLY K cards amo…

POJ 1365 Prime Land（数论）

题目链接: 传送门 Prime Land Time Limit: 1000MS Memory Limit: 10000K Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing…

[暑假集训--数论]poj1365 Prime Land

Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing sequence of all prime numbers. We know that x > 1 can be represented in only…

数学--数论--POJ1365——Prime Land

Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing sequence of all prime numbers. We know that x > 1 can be represe…