Tanya and Candies】的更多相关文章

Tanya and Candies time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output Tanya has nn candies numbered from 11 to nn . The ii -th candy has the weight aiai . She plans to eat exactly n−1n−1 candie…
Tanya has nn candies numbered from 11 to nn. The ii-th candy has the weight aiai. She plans to eat exactly n−1n−1 candies and give the remaining candy to her dad. Tanya eats candies in order of increasing their numbers, exactly one candy per day. You…
http://codeforces.com/contest/1118/problem/B 题目大意,给你一个序列,删去一个数值之后,要求剩下序列奇数和偶数的和相同,问有多少种删法. 思路:预处理奇数和偶数和即可 (算法能力康复性训练中......) //看看会不会爆int!数组会不会少了一维! //取物问题一定要小心先手胜利的条件 #include <bits/stdc++.h> #pragma comment(linker,"/STACK:102400000,102400000&q…
题意:有\(n\)个数,你可以任意去除某个位置的元素然后得到一个新数组,使得新数组奇数位和偶数的元素相等,现在问你有多少种情况合法. 题解:先求个后缀和,然后遍历,记录奇数和偶数位置的前缀和,删去\(i\)位置的元素,意味着原来\(i\)位置之后的奇数和变成了偶数和,偶数和变成了奇数和,将前缀和与差位的后缀和相加判断一下即可. 代码: int n; ll a[N]; ll suf1[N],suf2[N]; ll cnt1,cnt2; int main() { ios::sync_with_std…
A. Water Buying 链接:http://codeforces.com/contest/1118/problem/A 实现代码: #include<bits/stdc++.h> using namespace std; #define ll long long int main() { ll n,a,b,m; cin>>n; ;i <= n;i ++){ cin>>m>>a>>b; <= b) cout<<m*a…
Codeforces Round #540 (Div. 3) 题目链接:https://codeforces.com/contest/1118 题目太多啦,解释题意都花很多时间...还有事情要做,就选一些题来写吧. B. Tanya and Candies 题意: 在n个数中任意删去一个,如果这个数被删去后,剩余数的奇数和以及偶数和相等,那么就定义这个数为"好数".现在问这n个数中有多少个“好数”. 题解: 预处理出奇数前缀和.偶数前缀和,删去一个数后所有的奇数位置和 就为前面的奇数和…
B. Tanya and Postcard time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Little Tanya decided to present her dad a postcard on his Birthday. She has already created a message — string s of le…
Time Limit: 5000MS Memory Limit: 131072K Case Time Limit: 2000MS Description N children are sitting in a circle to play a game. The children are numbered from 1 to N in clockwise order. Each of them has a card with a non-zero integer on it in his/her…
题目链接:http://codeforces.com/problemset/problem/518/B 题目意思:给出字符串 s 和 t,如果 t 中有跟 s 完全相同的字母,数量等于或者多过 s,就将 s 这个数量加到 YAY! 的答案里,少于的话就加 t 中有的数量:如果 t 中有跟 s 相同的字母但是大小写不对应(例如A-a,z-Z),就加到 WHOOPS 的答案里. 举个例子就很容易明白了.例如 s 和 t 分别为: ncMeXssLHS uwyeMcaFatpInZVdEYpwJQSn…
Candies Time Limit: 1500MS   Memory Limit: 131072K Total Submissions: 22177   Accepted: 5936 Description During the kindergarten days, flymouse was the monitor of his class. Occasionally the head-teacher brought the kids of flymouse's class a large b…