题意:       给你一个n*m的矩阵,上面只有两种字符,X或者O,每次可以同时改变相同颜色的一个连通块,上下左右连通才算连通,用最小的步数把这个图弄成全是X或者全是O,题意要是没看懂看下面的样例. Sample Input 2 2 2 OX OX 3 3 XOX OXO XOX Sample Output 1 2 Hint For the second sample, one optimal solution is: Step 1. flip (2, 2) XOX OOO XOX Step…

Paint the Grid Reloaded Time Limit: 2 Seconds      Memory Limit: 65536 KB Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are…

Zoj 3781(构造) Zoj 3781 As we all know, Coach Gao is a talented chef, because he is able to cook M dishes in the same time. Tonight he is going to have a hearty dinner with his girlfriend at his home. Of course, Coach Gao is going to cook all dishes hi…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=5268 题目大意:字符一样并且相邻的即为连通.每次可翻转一个连通块X(O)的颜色,问至少改变几次使得图上所有字符都相等. 解题思路: 1) dfs( 建图 ) ,因为翻转的时候每翻转连通块中一个整个连通块都翻转,这样你可以将其看成一个有边相连的无向图,每个边的两个顶点颜色都不一样. 2) bfs( 寻找最优解 ) , 建完图后就需要翻转计算最优解,可以枚举从每一点开始…

题目: Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are in the same color, or there exists a cell C connected to both A and B.…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 Time Limit: 2 Seconds      Memory Limit: 65536 KB Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are calle…

题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two cells A and B are called connected if they share an edge and they are in…

LINK:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3781 题意:n*m只由OX组成的矩阵,可以选择某一连通块变成另一个字符,问整个矩阵变成相同的最小次数 思路:对所有连通块编号,根据是否与其他联通块相连建边,最后得到图后枚举以某起点(代表某连通块)所能到的最大距离求它们的最小值即可. 关键还是在于模型的转换,这方面我好像有点欠缺orz /** @Date : 2017-03-30-15.09 * @Author…

题目大意: 给一个n*m的X O构成的格子,对一个点操作可以使与它相连通的所有一样颜色的格子翻转颜色(X—>O或O—>X),问给定的矩阵最少操作多少次可以全部变成一样的颜色. 思路: 1.每次操作都将本身所在的连通块与和自己相邻的不同颜色的连通块变成同一种颜色,也就是变成一个连通块了,那么要使n次操作后全部变成一样的颜色,也就是从某点出发到达其余所有点. 2.因此dfs把连通块缩成点,然后相邻的连通块之间建边,枚举以每个点为根的情况,bfs求出每种情况的深度,取最小的即为答案. 反思: 1.h…

Paint the Grid Reloaded Time Limit: 2000MS   Memory Limit: 65536KB   64bit IO Format: %lld & %llu [Submit]   [Go Back]   [Status] Description Leo has a grid with N rows and M columns. All cells are painted with either black or white initially. Two ce…