pid=1150">Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 5424    Accepted Submission(s): 2691 Problem Description As we all know, machine scheduling is a very classical pro…

二分图:https://blog.csdn.net/c20180630/article/details/70175814 https://blog.csdn.net/flynn_curry/article/details/52966283 匈牙利算法模板:https://blog.csdn.net/sunny_hun/article/details/80627351 例题:hdu 1150 Machine Schedule 参考:https://www.cnblogs.com/qq-star/p…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1150 Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6733    Accepted Submission(s): 3375 Problem Description As we all know, mach…

http://acm.hdu.edu.cn/showproblem.php?pid=1150 有两种机器,A机器有n种模式,B机器有m种模式,现在有k个任务需要执行,没切换一个任务机器就需要重启一次, 如果任务i在机器A上执行,A机器需要一个对应的模式A,如果在机器B上执行,机器A需要一个模式B. 一直就是机器A在切换模式,现在让你安排一种合理的任务执行顺序,让机器重启次数最少. 每个任务之间连一条边.二分图的最小顶点覆盖就是求最少的点可以连接所有的边,然后转化成最大匹配即可. 这题就是初始状态…

题意:有两台机器A和B,A有n种工作模式(0~n-1),B有m种工作模式(0~m-1),两台机器的初始状态都是在工作模式0处.现在有k(0~k-1)个工作,(i,x,y)表示编号为i的工作可以通过机器A的工作模式x完成,也可以通过机器B的工作模式y完成.机器必须重启后才能更换一种工作模式,问最少的重启次数. 分析: 1.重启次数最少,即工作模式种类最少,即用最少的工作模式完成所有工作. 2.将A的n种工作模式看做n个点,将B的m种工作模式看做m个点,即用最少的点(工作模式)覆盖所有的边(一条边代…

Machine Schedule Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1150 Description As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history.…

Machine Schedule Time Limit: 1 Sec  Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=1150 Description As we all know, machine scheduling is a very classical problem in computer science and has been studied for a very long history.…

Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5316    Accepted Submission(s): 2631 Problem Description As we all know, machine scheduling is a very classical problem in comput…

//两道大水……哦不 两道结论题 结论:二部图的最小覆盖数=二部图的最大匹配数 有向图的最小覆盖数=节点数-二部图的最大匹配数 //hdu 1150 #include<cstdio> #include<iostream> #include<cmath> #include<algorithm> #include<cstring> #include<cstdlib> #include<queue> #include<ve…

Machine Schedule Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 9461    Accepted Submission(s): 4755 Problem Description As we all know, machine scheduling is a very classical problem in compu…