uva 10918 - Tri Tiling(规律)】的更多相关文章

题目链接:uva 10918 - Tri Tiling 题目大意:给出n,计算用1*2的瓷砖有多少种方法铺满3*n的地方. 解题思路:和uva 10359 - Tiling有点相似,不过难度会比较大,公式c[i] = 4 * c[i - 2] - c[i - 4]. 推导过程:c[0] = 1, c[2] = 3, c[4] = c[2] * 3 + c[1] * 2, c[6] = c[4] * 3 + (c[0] + c[2]) * 2 .... 即c[i] = c[i - 2] * 3 +…
Tri Tiling Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1631    Accepted Submission(s): 928 Problem DescriptionIn how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sampl…
Tri Tiling Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2731    Accepted Submission(s): 1547 Problem Description In how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sam…
                                                                                Tri Tiling   Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10306   Accepted: 5237 Description In how many ways can you tile a 3xn rectangle with 2x1 domino…
Tri Tiling Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7841   Accepted: 4113 Description In how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sample tiling of a 3x12 rectangle.  Input Input consists of several t…
链接:http://acm.hdu.edu.cn/showproblem.php? pid=1143 Tri Tiling Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2799 Accepted Submission(s): 1585 Problem Description In how many ways can you tile a…
Tri Tiling Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 2118    Accepted Submission(s): 1211 Problem Description In how many ways can you tile a 3xn rectangle with 2x1 dominoes? Here is a sa…
状态:d[i]代表n=i时的方案数. 状态转移方程:d[i]=d[i-2]+2*(d[i-2]+d[i-4]+-+d[0]) i只会为偶数,奇数情况不存在,d[0]=1 找状态转移方程的时候画图更好理解. #include <iostream> #include <cstdio> #include <algorithm> using namespace std; int d[50]; int main() { int n; d[0]=1; d[2]=3; int sum…
http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2245 题意:求用1×2的棋子摆满n×m的棋盘的方案数.(n×m<=100) #include <bits/stdc++.h> using namespace std; long long d[2][1<<10], n, m; int main() { while…
  Time Limit:1000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status #include<cstdio> using namespace std; int f(int n) { ) ; ) ; else *f(n-)-f(n-); } int main() { int n; &&n!=-) ==) printf("%d\n",f(n));…