题目大意就是说两个人掷飞镖,飞镖在所给定的图形内就记一分,现在给定N个图形(圆.三角形和矩形),问每一次比赛(没人分别掷三次)谁赢. #include <map> #include <set> #include <stack> #include <queue> #include <cmath> #include <ctime> #include <vector> #include <cstdio> #inclu…

●赘述题目 10*10的房间内,有竖着的一些墙(不超过18个).问从点(0,5)到(10,5)的最短路. 按照输入样例,输入的连续5个数,x,y1,y2,y3,y4,表示(x,0--y1),(x,y2--y3),(x,y4--10)是墙壁. ●题解 方法:建图(用到简单计算几何)+最短路 ○记录下每个端点. ○包含起点,终点,以及每个墙的可以走的端点,如下图: ○然后枚举点,尝试两两组合连(线段)边,若该线不会撞在墙上,即不会与墙壁线段相交,就add_adge(). 效果图如下: 如何判断呢?…

Toy Storage Time Limit: 1000MS Memory Limit: 65536K Description Mom and dad have a problem: their child, Reza, never puts his toys away when he is finished playing with them. They gave Reza a rectangular box to put his toys in. Unfortunately, Reza is…

1007: [HNOI2008]水平可见直线 Time Limit: 1 Sec Memory Limit: 162 MB Description 在xoy直角坐标平面上有n条直线L1,L2,-Ln,若在y值为正无穷大处往下看,能见到Li的某个子线段,则称Li为可见的,否则Li为被覆盖的. 例如,对于直线:L1:y=x; L2:y=-x; L3:y=0则L1和L2是可见的,L3是被覆盖的. 给出n条直线,表示成y=Ax+B的形式(|A|,|B|<=500000),且n条直线两两不重合.求出所有可…

Area Time Limit: 1000MS Memory Limit: 10000K Description You are going to compute the area of a special kind of polygon. One vertex of the polygon is the origin of the orthogonal coordinate system. From this vertex, you may go step by step to the fol…

Segments Time Limit: 1000MS Memory Limit: 65536K Description Given n segments in the two dimensional space, write a program, which determines if there exists a line such that after projecting these segments on it, all projected segments have at least…

TOYS Time Limit: 2000MS Memory Limit: 65536K Description Calculate the number of toys that land in each bin of a partitioned toy box. Mom and dad have a problem - their child John never puts his toys away when he is finished playing with them. They g…

Pick-up sticks Time Limit: 3000MS Memory Limit: 65536K Description Stan has n sticks of various length. He throws them one at a time on the floor in a random way. After finishing throwing, Stan tries to find the top sticks, that is these sticks such…

题目链接 https://codeforces.com/gym/101917 E 题意:给定一个多边形(n个点),然后逆时针旋转A度,然后对多边形进行规约,每个点的x规约到[0,w]范围内,y规约到[0,h]范围内,输出规约后的结果. 解析:求出来 多边形的长和宽,再和w,h比较,对点按比例进行缩放就好了. (多边形旋转其实是绕给出的第一个点旋转,以为是绕原点wa了1发). AC代码 #include <bits/stdc++.h> #define Vector Point using nam…

https://www.luogu.org/problemnew/show/P1355 判断一个点和三角形的位置关系,最简单的思路就是用向量. 首先排除掉和三角形顶点重合的情况. 把三角形设计成一个首尾相接的三个向量,从三个向量的起点连线到P点构成新向量,叉乘判断方向.二维向量叉乘(x1,y1)×(x2,y2)=(x1y2-x2y1),方向是右手螺旋.那么判断正负号就知道他们在向量的哪一侧了. 在三角形中的应该在三个向量的同侧.而不在三角形中的会有一个方向与另外两个不同.在三角形上的显然就是存在…