[SQL] 不合并重复数据 union all】的更多相关文章

select * from A union select * from B --不合并重复行 select * from A union all select * from B --如果要对字段进行排序 select * from ( select id,... from A union all select id,... from B ) t order by ID…
本文主要总结数据库去掉重复数据的方法 去掉重复数据的方法: 第一种:distinct 根据单个字段去重,能精确去重: 作用在多个字段时,只有当这几个字段的完全相同时,才能去重: 关键字distinct只能放在SQL语句中的第一个,才会起作用 上图举例说明:图中student_name 为 test的同学有两位,不同的是班级 首先,单个字段 ->用distinct对student_name 进行筛选,单个字段查询的话,可以看到已经将一个重复的test学生记录去掉了 应用在多个字段时,可以看到此时两…
数据库UserInfo 删除重复数据 即删除重复的用户名手机号 同一个用户名手机号只保留一个用户 01.根据多个字段查询重复数据 with data1 as( select MobilePhone,Name from UserInfogroup by MobilePhone,Namehaving count(*)>1 ), 02.对重复数据分配编号 data2 as ( select u.*,row_number() over(partition by u.MobilePhone,u.Name…
1.如表中没有主键,先添加自动增长主键 alter table 表名 add 列名 int identity (1,1) primary key 2.删除重复数据 delete from 表名 where id not in (select min(id) from 表名 group by id) ------id1为新增自增的列,id为原来没有自增的id列 delete from DeceasedInformation where id1 not in (select MIN(id) from…
DELETE FROM Bus_TerminalMessage_Keywords WHERE Content IN (select Content from Bus_TerminalMessage_Keywords group by Content having count(Content) > 1) AND ID NOT IN (select min(Id) from Bus_TerminalMessage_Keywords group by Content having count(Cont…
删除重复数据 备份表 删除最早的评论…
--用SQL语句,删除掉重复项只保留一条 --在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢 --1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) --2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId…
用SQL语句,删除掉重复项只保留一条 在几千条记录里,存在着些相同的记录,如何能用SQL语句,删除掉重复的呢 1.查找表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断 select * from people where peopleId in (select peopleId from people group by peopleId having count(peopleId) > 1) 2.删除表中多余的重复记录,重复记录是根据单个字段(peopleId)来判断,只留有…
1.查询单列重复: select * from test where name in (select name from test group by name having count (name) > 1) 2.查询多列重复: SELECT a.* FROM test a,( SELECT name,code FROM test GROUP BY name,code HAVING COUNT(1)>1 ) AS b WHERE a.name=b.name AND a.code=b.code…
1.取时间最新的记录 不分组有重复(多条CreateTime一样的都是最新记录) select * from test t where pid in ( select PId from Test t where time=(select max(time) from Test t1 where t1.PId=t.PId) group by Pid ) and time=(select max(time) from Test t1 where t1.PId=t.PId) 2.分组后取时间最新的记录…