LeetCode: 620 Not Boring Movies(easy)】的更多相关文章

题目: X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions. Please write a SQL query to output movies with an odd numbered ID and a description that…
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions. Please write a SQL query to output movies with an odd numbered ID and a description that is n…
https://leetcode.com/problems/not-boring-movies/description/ 不管题目简不简单,现在先熟悉语法. 直接用where语句判断即可,判断奇偶可以用 % # Write your MySQL query statement below select * from cinema = and description != 'boring' order by rating desc; 还有用 & 也行 # Write your MySQL quer…
题目标签: 题目给了我们一个 cinema 表格, 让我们找出 不无聊的电影,并且id 是奇数的,降序排列. 比较直接简单的,具体看code. Java Solution: Runtime:  149 ms, faster than 29.21% Memory Usage: N/A 完成日期:07/02/2019 关键点:NOT IN # Write your MySQL query statement below SELECT id, movie, description, rating FR…
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions. Please write a SQL query to output movies with an odd numbered ID and a description that is n…
X city opened a new cinema, many people would like to go to this cinema. The cinema also gives out a poster indicating the movies’ ratings and descriptions. Please write a SQL query to output movies with an odd numbered ID and a description that is n…
leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…
索引:[LeetCode] Leetcode 题解索引 (C++/Java/Python/Sql) Github: https://github.com/illuz/leetcode 038. Count and Say (Easy) 链接: 题目:https://leetcode.com/problems/Count-and-Say/ 代码(github):https://github.com/illuz/leetcode 题意: 数数.第一个是 1,第二个是数前一个数:1 个 1,就是 11…
SQL架构 Create table If Not Exists cinema (id ), description varchar(), rating , )) Truncate table cinema insert into cinema (id, movie, description, rating) values (', 'War', 'great 3D', '8.9') insert into cinema (id, movie, description, rating) value…
终于刷完了leetcode的前250道题的easy篇.好吧,其实也就60多道题,但是其中的套路还是值得被记录的. 至于全部code,请移步github,题目大部分采用python3,小部分使用C,如有问题和建议,欢迎指正. String 有一个string库,可以返回各种string的汇总,很值得用. 当题目中需要实现字符串替代的时候,python中有一个自带的translate()函数可以实现这个功能,具体可见Python3字符串替换replace(),translate(),re.sub()…