LeetCode 题解之Add Two Numbers II】的更多相关文章

1.题目描述 2.分析 首先将链表翻转,然后做加法. 最后将结果链表翻转. 3.代码 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* L1 = reverseList( l1 ); ListNode* L2 = reverseList( l2 ); ListNode* head = ); ListNode* result = head; ListNode* p1 = L1; ListNode* p2 = L2; ;…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 先求和再构成列表 使用栈保存节点数字 类似题目 日期 题目地址:https://leetcode.com/problems/add-two-numbers-ii/description/ 题目描述 You are given two non-empty linked lists representing two non-negative intege…
我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ ` 2.Add Two Numbers [M] Add Two Numbers M 题目 思路 代码 更精巧的代码 题目 You are given two linked lists representing two non-negative numbers. The…
题目: You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two num…
You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers…
题目大意:使用链表表示的两个整数,计算出其和,以同样的形式返回. Input: (2 -> 4 -> 3) + (5 -> 6 -> 4) Output: 7 -> 0 -> 8 觉得做OJ最大的问题是有时看不懂题目. 其实是这样的,一个链表代表一个非负整数数,是从右往左看的: (2 -> 4 -> 3) = 342: (5 -> 6 -> 4)=465: 342+465=7 -> 0 -> 8=807: 逆序其实是很大很大的便利!!…
1.题目描述 2.题目描述 题目思路可以参考合并单链表的思路,定义一个全局 进位标志,如果两个数值相加得到需要进位,则将进位标志置为1 . 3.代码 ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) { ListNode* head = ) ; ListNode* result = head; ListNode* p1 = l1; ListNode* p2 = l2; ; while( p1 != NULL && p2 != NULL…
You are given two linked lists representing two non-negative numbers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list. You may assume the two numbers do not con…
445. 两数相加 II 445. Add Two Numbers II 题目描述 给定两个非空链表来代表两个非负整数.数字最高位位于链表开始位置.它们的每个节点只存储单个数字.将这两数相加会返回一个新的链表. 你可以假设除了数字 0 之外,这两个数字都不会以零开头. 进阶: 如果输入链表不能修改该如何处理?换句话说,你不能对列表中的节点进行翻转. LeetCode445. Add Two Numbers II中等 示例: 输入: (7 -> 2 -> 4 -> 3) + (5 ->…
Question 445. Add Two Numbers II Solution 题目大意:两个列表相加 思路:构造两个栈,两个列表的数依次入栈,再出栈的时候计算其和作为返回链表的一个节点 Java实现: public ListNode addTwoNumbers(ListNode l1, ListNode l2) { Stack<Integer> s1 = new Stack<>(); Stack<Integer> s2 = new Stack<>();…