我现在在做一个叫<leetbook>的开源书项目,把解题思路都同步更新到github上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 007. Reverse Integer[E]——处理溢出的技巧 题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 思路 这题完全没丝毫的难度,任何人几分钟都可以写…

题目: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only hold integers with…

7.Reverse Integer Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only stor…

7. Reverse Integer 题目描述: Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note: Assume we are dealing with an environment which could o…

Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 click to show spoilers. Have you thought about this? Here are some good questions to ask before coding. Bonus points for you if you have already thought throu…

作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 公众号:负雪明烛 本文关键词:整数,反转,题解,Leetcode, 力扣,Python, C++, Java 目录 题目描述 题目大意 解题方法 转成字符串 数学 日期 题目地址:https://leetcode.com/problems/reverse-integer/description/ 题目描述 Given a 32-bit signed integer, reverse d…

一天一道LeetCode系列 (一)题目 Reverse digits of an integer. Example1: x = 123, return 321 Example2: x = -123, return -321 (二)解题 这题看上去很简单,动笔一挥之下,写出如下代码: class Solution { public: int reverse(int x) { bool flag = false; if(x<0) { x=-k; flag = true; } long result…

这是悦乐书的第143次更新,第145篇原创 01 看题和准备 今天介绍的是LeetCode算法题中Easy级别的第2题(顺位题号是7),给定32位有符号整数,然后将其反转输出.例如: 输入: 123 输出: 321 输入: -123 输出: -321 输入: 120 输出: 21 给定反转整数范围: [−2^31, 2^31 − 1],即在int的最小值.最大值之间,如果反转整数超过此范围,则返回0. 本次解题使用的开发工具是eclipse,jdk使用的版本是1.8,环境是win7 64位系统,…

Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 Note:Assume we are dealing with an environment which could only hold integers within t…

这题简单,也花了我好长时间,我自己写的code比较麻烦,也没啥技巧:按正负性分类执行,先转化成字符串,用stringbuilder进行旋转,如果超出范围了就用try catch public int reverse(int x) { try { int result = 0; if (x == 0) { return x; } else if (x < 0) { String num = Integer.toString(0 - x); String newNum = new StringBui…