POJ 2636:Electrical Outlets】的更多相关文章

Electrical Outlets Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9597   Accepted: 7186 Description Roy has just moved into a new apartment. Well, actually the apartment itself is not very new, even dating back to the days before people…
Electrical Outlets Time Limit: 2 Seconds      Memory Limit: 65536 KB Roy has just moved into a new apartment.Well, actually the apartment itself is not very new, even dating back to the days before people had electricity in their houses. Because of t…
Problem Description Roy has just moved into a new apartment. Well, actually the apartment itself is not very new, even dating back to the days before people had electricity in their houses. Because of this, Roy's apartment has only one single wall ou…
#include<iostream> #include<stdio.h> using namespace std; int main() { //freopen("acm.acm","r",stdin); int num; int sum; int time; int a; cin>>time; while(time --) { sum = ; cin>>num; sum -= num - ; while(num --…
感谢范意凯.陈申奥.庞可.杭业晟.王飞飏.周俊豪.沈逸轩等同学的收集整理.   题号:1003 Hangover求1/2+1/3+...1/n的和,问需多少项的和能超过给定的值 类似于Zerojudge a625 题号:1004 Financial Management 求12个实数的平均值   题号:1008 Maya Calendar 玛雅历 此题语言可选中文 PS:注意Haab历的日期是从0开始,而Tzolkin历的日期是从1开始   题号:1067 取石子游戏 此题语言为中文 PS:请百…
2992.357000 1000 A+B Problem1214.840000 1002 487-32791070.603000 1004 Financial Management880.192000 1003 Hangover792.762000 1001 Exponentiation752.486000 1006 Biorhythms705.902000 1005 I Think I Need a Houseboat686.540000 1011 Sticks647.566000 1007…
各种杂题,水题,模拟,包括简单数论. 1001 A+B 1002 A+B+C 1009 Fat Cat 1010 The Angle 1011 Unix ls 1012 Decoding Task 1019 Grandpa's Other Estate 1034 Simple Arithmetics 1036 Complete the sequence! 1043 Maya Calendar 1054 Game Prediction 1057 Mileage Bank 1067 Rails 10…
杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…
/**************************************************************************** * What is Cross Linux From Scratch? * 说明: * 本文想知道交叉编译的LFS到底是什么. * * 2016-3-23 深圳 南山平山村 曾剑锋 ***************************************************************************/ 参考文章…
容错声明: ①题目选自https://acm.ecnu.edu.cn/,不再检查题目删改情况 ②所有代码仅代表个人AC提交,不保证解法无误 E0001  A+B Problem First AC: 2017-10-13       Latest Modification: 2018-02-28 #include<bits/stdc++.h> using namespace std; int a,b; int main() { cin>>a>>b; cout<<…