Given a singly linked list where elements are sorted in ascending order, convert it to a height balanced BST. 题意:给定一个有序的链表,将其转换成平衡二叉搜索树 思路: 二分法 要构建一个平衡二叉树,二分法无疑是合适的,至于如何分是的代码简洁,就需要用到递归了. class Solution { public: // find middle element of the list Lis…