Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29344    Accepted Submission(s): 7688 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1007 Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 62916    Accepted Submission(s): 16609 Problem Description Have you ever played…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 58566    Accepted Submission(s): 15511 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 47104    Accepted Submission(s): 12318 Problem Description Have you ever played quoit in a playground? Quoit is a game in which fla…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 25335    Accepted Submission(s): 6716 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1007 题意:给出n个点求最短的两点间距离除以2. 题解:简单的分治. 其实分治就和二分很像二分的写dfs然后复杂度就是log(n*log(n)*log(n)) #include <iostream> #include <cstring> #include <cstdio> #include <algorithm> #include <cmath> u…

Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded.In the field of Cyberground, the position of each toy is fixed, and the ring is carefull…

暂鸽 #include<cstdio> #include<algorithm> #include<cstring> #include<cmath> #define N 100010 using namespace std; void chkmin(double x,double y) {if (x>y) x=y;} int n; struct point { double x,y; point(){}; point(double _x,double _…

http://acm.hdu.edu.cn/showproblem.php?pid=1007 上半年在人人上看到过这个题,当时就知道用分治但是没有仔细想... 今年多校又出了这个...于是学习了一下平面内求最近点对的算法...算导上也给了详细的说明 虽然一看就知道直接用分治O(nlogn)的算法 , 但是平面内最近点对的算法复杂度证明我看了一天也没有完全看明白... 代码我已经做了一些优化...但肯定还能进一步优化..我是2s漂过的非常惭愧...(甚至优化以后时间还多了...不明白原因 /***…

Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded.In the field of Cyberground, the position of each toy is fixed, and the ring is carefull…

传送门 Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded…

原题地址 题目大意 查询平面内最近点对的距离,输出距离的一半. 暴力做法 枚举每一个点对的距离直接判断,时间复杂度是 $ O(n^2) $,对于这题来说会超时. 那么我们考虑去优化这一个过程,我们在求距离的过程中其实有很多的计算是没有必要的,比如已经有一个暂时的最小值 $ d \(,如果有\) dis>d $,那么这个 $ dis $是没有贡献的,那么我们怎么除去这些不必要的答案呢? 我们可以考虑分治,假设已经求出了两个小区间 $ A , B $的最小值,那么合并的大区间 $ C $ 的最小值实…

题意:求平面最近点对之间的距离 解:首先可以想到枚举的方法,枚举i,枚举j算点i和点j之间的距离,时间复杂度O(n2). 如果采用分治的思想,如果我们知道左半边点对答案d1,和右半边点的答案d2,如何求跨两边点之间的答案呢?显然只用枚举中线两边d=min(d1,d2)范围的点,并且每个点都只需要枚举上下范围在d以内的点,显然这样的点不会很多. #include <algorithm> #include <iostream> #include <cstring> #inc…

大致题意:给N个点,求最近点对的距离 d :输出:r = d/2. // Time 2093 ms; Memory 1812 K #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #define eps 1e-8 #define maxn 100010 #define sqr(a) ((a)*(a)) using namespace std; int sig(dou…

题意: 给出平面上的n个点,问任意点对之间的最短距离是多少? 思路: 先将所有点按照x坐标排序,用二分法将n个点一分为二个部分,递归下去直到剩下两或一个点.对于一个部分,左右部分的答案分别都知道,那么可能的答案就是min(left_ans,right_ans) .注意更小的点对可能一个在左,一个在右.所以还得处理两个边内的紧靠着的部分,如果左边的一个点到达中线的距离已经超过当前最短距离,那么这个点到达右边任意一个点也不会是最短距离了.同时,若一左一右的两个点的y距离已经超过目前最短距离,那么也不…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 29694    Accepted Submission(s): 7788 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

Quoit Design Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded. In the field of Cyberground, the position of each toy is fixed, and the ri…

意甲冠军:给n坐标点.半一对点之间的距离所需的距离最近. 分析:分而治之的方法,最近点. #include<iostream> #include<algorithm> #include<cmath> using namespace std; #define N 100005 double min(double a,double b) { return a<b? a:b; } struct POINT { double x,y; }; POINT point[N],…

Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded. In the field of Cyberground, the position of each toy is fixed, and the ring is careful…

题意:有n个点,问其中某一对点的距离最小是多少 分析:分治法解决问题:先按照x坐标排序,求解(left, mid)和(mid+1, right)范围的最小值,然后类似区间合并,分离mid左右的点也求最小值 POJ 3714 #include <cstdio> #include <cstring> #include <cmath> #include <algorithm> const int N = 1e5 + 5; const double INF = 1e…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1007 Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42865    Accepted Submission(s): 11128 Problem Description Have you ever played…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 30505    Accepted Submission(s): 8017 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

主题: Quoit Design Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 136 Accepted Submission(s): 77   Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat rin…

Quoit Design Time Limit: 5 Seconds      Memory Limit: 32768 KB Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys encircled awarded. In the field of Cyberground, the position of…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 28539    Accepted Submission(s): 7469 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

题目链接 Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 29547    Accepted Submission(s): 7741 Problem Description Have you ever played quoit in a playground? Quoit is a game in which…

Quoit Design 看懂题意以后发现就是找平面最近点对间距离除以2. 平面上最近点对是经典的分治,我的解析 直接上代码 #include<bits/stdc++.h> using namespace std; #define int long long const int N=1000005; const double inf=1e12; struct node{ double x,y; }p[N]; bool cmp(node a,node b) { if(a.x==b.x)retur…

---恢复内容开始--- Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 47126    Accepted Submission(s): 12323 Problem Description Have you ever played quoit in a playground? Quoit is a game…

Quoit Design Time Limit: 10000/5000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 48729    Accepted Submission(s): 12823 Problem Description Have you ever played quoit in a playground? Quoit is a game in which flat…

http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1107 Quoit Design Time Limit: 5 Seconds      Memory Limit: 32768 KB Have you ever played quoit in a playground? Quoit is a game in which flat rings are pitched at some toys, with all the toys…