Maximum Product UVA - 11059】的更多相关文章

Problem D - Maximum Product Time Limit: 1 second Given a sequence of integers S = {S1, S2, ..., Sn}, you should determine what is the value of the maximum positive product involving consecutive terms ofS. If you cannot find a positive sequence, you s…
最大乘积 Maximum Product 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=84562#problem/B 解题思路: 题目意思是输入n个元素组成的序列S,找出一个乘积最大的连续子序列.若这个数不是正数,则输出0(表示无解).分析 ,连续子序列有两个要素:起点和终点,因此只需要枚举起点和终点即可.分析最大可能的乘积不会超过10的18次方,所以用 long long 来存储即可. 程序代码: #include <c…
Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of themaximum positive product involving consecutive terms of S. If you cannot find a positive sequence,you should consider 0 as the value of the maximum pr…
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注意long long  long long  longlong !!!!!!   还有 printf的时候 明明longlong型的答案 用了%d  WA了也看不出,这个细节要注意!!! #include <cstdio> ]; int main() { ;long long ans,sum; while(~scanf("%d",&n)) { ;i<n;i++) scanf("%d",&a[i]); ans=; ;i<n;i…
题目链接:https://vjudge.net/contest/210334#problem/B 题目大意:Given a sequence of integers S = {S1, S2, . . . , Sn}, you should determine what is the value of the maximum positive product involving consecutive terms of S. If you cannot find a positive sequen…
[题意]:乘积最大的子序列.n∈[1,10],s∈[-10,10] [代码]: #include<bits/stdc++.h> using namespace std; int a[105]; #define LL long long int main() { int n,f=0; LL s,ma; while(~scanf("%d",&n)) { f++; ma=0; for(int i=0;i<n;i++) scanf("%d",&am…
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] C语言for循环练习题 [代码] /* 1.Shoud it use long long ? 2.Have you ever test several sample(at least therr) yourself? 3.Can you promise that the solution is right? At least,the main ideal 4.use the puts("") or putchar()…
UVA.10305 Maximum Product (暴力) 题意分析 直接枚举起点和重点,然后算出来存到数组里面,sort然后取最大值即可. 代码总览 #include <iostream> #include <iostream> #include <cstdio> #include <algorithm> #include <cstring> #include <sstream> #include <set> #inc…
https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=2000 题意:找出乘积最大的连续子序列. 思路:这道题目我挺无语的,一直超时,也不知道是哪里出了问题,反正最后试来试去终于有种办法成功了.不过好像这道题目不需要考虑输出0的情况吧. #include<iostream> using namespace std; int main(…