RemoveDuplicatesfromSortedList】的更多相关文章

/** * Source : https://oj.leetcode.com/problems/remove-duplicates-from-sorted-list/ * * * Given a sorted linked list, delete all duplicates such that each element appear only once. * * For example, * Given 1->1->2, return 1->2. * Given 1->1-&g…
给定一个排序链表,删除所有重复的元素,使得每个元素只出现一次. 示例 1: 输入: 1->1->2 输出: 1->2 示例 2: 输入: 1->1->2->3->3 输出: 1->2->3 思路 :判断当前结点与其下一个结点值是否相等,相等则删除下一个节点 class Solution { public: ListNode* deleteDuplicates(ListNode* head) { ListNode* cur = head; while(c…
题意略: 思路:先造一个点它与所有点的值都不同,那么只要后面两个点的值相同就开始判断后面是不是也相同,最后将相同的拆下来就可以了. #include<iostream> #include<cstdio> using namespace std; struct ListNode { int val; ListNode *next; ListNode(int x) : val(x), next(NULL) {} }; class Solution { public: ListNode…
Question Given a sorted linked list, delete all duplicates such that each element appear only once. For example, Given1->1->2, return1->2. Given1->1->2->3->3, return1->2->3. Solution 判断当前节点和下一个节点是否相等,相等就跳过. Code /** * Definition…
I.Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given1->1->2, return1->2.Given1->1->2->3->3, return1->2->3. PS:遍历,而后记录pre,并删除后续重复node /** * Definition for singly-linked li…
Given a sorted linked list, delete all duplicates such that each element appear only once. For example,Given 1->1->2, return 1->2.Given 1->1->2->3->3, return 1->2->3. 移除有序链表中的重复项需要定义个指针指向该链表的第一个元素,然后第一个元素和第二个元素比较,如果重复了,则删掉第二个元素,…
利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectangle-in-histo…
一直直到bug-free.不能错任何一点. 思路不清晰:刷两天. 做错了,刷一天. 直到bug-free.高亮,标红. 185,OA(YAMAXUN)--- (1) findFirstDuplicate string in a list of string. import java.util.HashSet; import java.util.Set; public class Solution { public static void main(String[] args) { String[…
463. Island Perimeterhttps://leetcode.com/problems/island-perimeter/就是逐一遍历所有的cell,用分离的cell总的的边数减去重叠的边的数目即可.在查找重叠的边的数目的时候有一点小技巧,就是沿着其中两个方向就好,这种题目都有类似的规律,就是可以沿着上三角或者下三角形的方向来做.一刷一次ac,但是还没开始注意codestyle的问题,需要再刷一遍. class Solution { public: int islandPerime…
leetcode代码 利用堆栈:http://oj.leetcode.com/problems/evaluate-reverse-polish-notation/http://oj.leetcode.com/problems/longest-valid-parentheses/ (也可以用一维数组,贪心)http://oj.leetcode.com/problems/valid-parentheses/http://oj.leetcode.com/problems/largest-rectang…