Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5,6], 5 → 2 [1,3,5,6], 2…

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 →…

Leetcode之二分法专题-35. 搜索插入位置(Search Insert Position) 给定一个排序数组和一个目标值,在数组中找到目标值,并返回其索引.如果目标值不存在于数组中,返回它将会被按顺序插入的位置. 你可以假设数组中无重复元素. 示例 1: 输入: [1,3,5,6], 5 输出: 2 示例 2: 输入: [1,3,5,6], 2 输出: 1 示例 3: 输入: [1,3,5,6], 7 输出: 4 示例 4: 输入: [1,3,5,6], 0 输出: 0 class So…

本人编程小白,如果有写的不对.或者能更完善的地方请个位批评指正! 这个是leetcode的第35题,这道题的tag是数组,python里面叫list,需要用到二分搜索法 35. Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were in…

Sqrt(x) Implement int sqrt(int x). Compute and return the square root of x. 注:这里的输入输出都是整数说明不会出现 sqrt(7)这种情况,思路一就是应用二分法进行查找.每次给出中间值,然后比对cur的平方与目标值的大小.需要先设定两个变量用来存放左右游标. 这里要考虑一下整型溢出的问题,另外,即使不能开出整数的也要近似给出整数部分,不能忽略. 代码如下: int Solution::mySqrt(int x) { //…

Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Here are few examples. [1,3,5…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 35: Search Insert Positionhttps://oj.leetcode.com/problems/search-insert-position/ Given a sorted array and a target value, return the index if the target is found.If not, return the index…

leetcode - 35. Search Insert Position - Easy descrition Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the arr…

704. Binary Search 1.使用start+1 < end,这样保证最后剩两个数 2.mid = start + (end - start)/2,这样避免接近max-int导致的溢出 3.start.end直接等于mid 4.最后比较两个位置 class Solution { public: int search(vector<int>& nums, int target) { if(nums.empty()) ; ; ; int mid; < end){ m…

leetcode-algorithms-35 Search Insert Position Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order. You may assume no duplicates in the array. Exampl…