Problem Description There are N boys in CodeLand.Boy i has his coding skill Ai.CRB wants to know who has the suitable coding skill.So you should treat the following two types of queries.Query 1: 1 l vThe coding skill of Boy l has changed to v.Query 2…

题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5412 CRB and Queries Description There are $N$ boys in CodeLand. Boy i has his coding skill $A_{i}$. CRB wants to know who has the suitable coding skill. So you should treat the following two types of qu…

题目链接 动态区间第k小,但是这道题的话用主席树+树状数组套线段树的空间复杂度是O(nlog2n)会爆掉. 另一种替代的方法是用树状数组套平衡树,空间复杂度降到了O(nlogn),但我感觉平衡树是个挺恶心的东西,而且时间复杂度是O(nlog3n),比主席树还多了个logn. 最高效的方法是用一个叫整体二分的东西算法,它的基本思想是这样的: 假设当前所有查询的答案范围都在[l,r]之间,设mid=(l+r)/2,那么我们只处理所有修改后的值在[l,mid]中的修改操作,把不需要执行的修改操作全部扔…

题意 动态区间第k大 (n<=100000,m<=100000) 题解 整体二分的应用. 与静态相比差别不是很大.(和CDQ还有点像)所以直接上代码. #include<iostream> #include<cstdio> #include<cstring> #include<cstdio> #include<algorithm> using namespace std; ; struct query{ int x,y,type,k,…

CRB and Queries Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1602    Accepted Submission(s): 409 Problem Description There are N boys in CodeLand.Boy i has his coding skill Ai.CRB wants to…

CRB and Queries Time Limit: 12000/6000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 533    Accepted Submission(s): 125 Problem DescriptionThere are N boys in CodeLand.Boy i has his coding skill Ai.CRB wants to k…

题目链接:http://acm.hdu.edu.cn/showproblem.php? pid=5412 Problem Description There are N boys in CodeLand. Boy i has his coding skill Ai. CRB wants to know who has the suitable coding skill. So you should treat the following two types of queries. Query 1…

CRB and Queries Time Limit: 6000 MS Memory Limit: 131072 K Problem Description There are N boys in CodeLand. Boy i has his coding skill Ai. CRB wants to know who has the suitable coding skill. So you should treat the following two types of queries. Q…

传送门 刚觉得最近写代码比较顺畅没什么Bug,cdq分治真是我的一个噩梦.. 整体二分模板题,带修改的区间第k小. vjudge不知抽什么风,用不了,hdu忘了密码了一直在那里各种试,难受.. 写得比较鬼畜. 整体二分,传了三个l,r分别是二分答案的 el ,er ,对当前答案可能有贡献的修改区间的 l , r ,答案在当前二分区间中的询问区间 ql, qr 每次对el, er 取个mid,然后修改区间是按时间排好序的,按时间扫过去,在修改值大于mid的地方+1(区间第k小等价于大于等于它的数有…

题目链接: http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=1112 题意: 求动态区间第K大. 分析: 把修改操作看成删除与增加,对所有操作进行整体二分. 代码: #include<cstdio> #include<iostream> #include<cstring> using namespace std; #define pr(x) cout << #x << &quo…