leetcode717】的更多相关文章

版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - Leetcode717. 1比特与2比特字符 - 题解 Leetcode 717. 1-bit and 2-bit Characters 在线提交: https://leetcode-cn.com/problems/1-bit-and-2-bit-characters/ 题目描述 有两种特殊字符.第一…
We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c…
We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11). Now given a string represented by several bits. Return whether the last character must be a one-bit c…
class Solution { public: bool isOneBitCharacter(vector<int>& bits) { int len = bits.size(); ) { ] == ) { return true; } else { return false; } } ; i < len; i++) { && bits[i] == ) { return true; } ) { continue; } ) { i++; continue; } }…
有两种特殊字符.第一种字符可以用一比特0来表示.第二种字符可以用两比特(10 或 11)来表示. 现给一个由若干比特组成的字符串.问最后一个字符是否必定为一个一比特字符.给定的字符串总是由0结束. 示例 1: 输入: bits = [1, 0, 0] 输出: True 解释: 唯一的编码方式是一个两比特字符和一个一比特字符.所以最后一个字符是一比特字符. 示例 2: 输入: bits = [1, 1, 1, 0] 输出: False 解释: 唯一的编码方式是两比特字符和两比特字符.所以最后一个字…
717. 1比特与2比特字符 LeetCode717. 1-bit and 2-bit Characters 题目描述 有两种特殊字符.第一种字符可以用一比特0来表示.第二种字符可以用两比特(10 或 11)来表示. 现给一个由若干比特组成的字符串.问最后一个字符是否必定为一个一比特字符.给定的字符串总是由0结束. 示例 1: 输入: bits = [1, 0, 0] 输出: True 解释: 唯一的编码方式是一个两比特字符和一个一比特字符.所以最后一个字符是一比特字符. 示例 2: 输入: b…