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BZOJ 1112. 题意相当于在一个长度为$k$的区间内选择一个数$s$使$\sum_{i = 1}^{k}\left | a_i - s \right |$最小. 很显然是中位数. 然后只要写一个能查询长度为$k$的区间的中位数,以及小于和大于这个中位数的总和和个数的数据结构即可. 线段树平衡树对顶堆随便维护. 我选择权值线段树. 时间复杂度$O(nlogn)$. Luogu上还需要输出方案. Code: #include <cstdio> #include <cstring>…
https://www.threadingbuildingblocks.org/docs/help/index.htm Parallelizing Data Flow and Dependency Graphs In addition to loop parallelism, the Intel® Threading Building Blocks (Intel® TBB) library also supports graph parallelism. It's possible to cre…
Building Blocks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 751    Accepted Submission(s): 164 Problem Description After enjoying the movie,LeLe went home alone. LeLe decided to build block…
The main building blocks of both XML and HTML documents are elements. The Building Blocks of XML Documents Seen from a DTD point of view(从dtd的角度来看), all XML documents (and HTML documents) are made up by the following building blocks: Elements Attribu…
之前忙于搬家移居,无暇顾及博客,今天终于得闲继续我的“政治课”了,希望之后至少能够补完TOGAF方面的内容.从前面文章可以看出,笔者并无太多能力和机会对TOGAF进行理论和实际的联系,仅可对标准的文本进行翻译和整理,间或掺杂点个人理解,望各位看官海涵,如能有所帮助则足以欣慰. 5. 构建块(Building Blocks) 架构构建块可以说是企业架构内容的核心,也是企业架构开发方法的最终产物.与此相比,架构交付物所面向的是企业架构开发过程,架构制品则可以看作是企业架构内容的表现形式和使用方式,而…
TOGAF架构内容框架之构建块(Building Blocks) 之前忙于搬家移居,无暇顾及博客,今天终于得闲继续我的“政治课”了,希望之后至少能够补完TOGAF方面的内容.从前面文章可以看出,笔者并无太多能力和机会对TOGAF进行理论和实际的联系,仅可对标准的文本进行翻译和整理,间或掺杂点个人理解,望各位看官海涵,如能有所帮助则足以欣慰. 5. 构建块(Building Blocks) 架构构建块可以说是企业架构内容的核心,也是企业架构开发方法的最终产物.与此相比,架构交付物所面向的是企业架构…
Problem Description After enjoying the movie,LeLe went home alone. LeLe decided to build blocks. LeLe has already built  piles. He wants to move some blocks to make  consecutive piles with exactly the same height . LeLe already put all of his blocks…
原文地址:https://blog.sessionstack.com/how-javascript-works-the-building-blocks-of-web-workers-5-cases-when-you-should-use-them-a547c0757f6a How JavaScript works: The building blocks of Web Workers + 5 cases when you should use them JavaScript的工作原理:Web W…
题面 传送门:https://www.luogu.org/problemnew/show/P3469 Solution 先跟我大声念: poi! 然后开始干正事. 首先,我们先把题目中的点分为两类:去除这个点能把图分为几个部分的,去除这个点不影响整个图的连通性的. 如下图: 点上的数字表示这个点的搜索序. 我们称这些对连通性有影响的点为割点. 先假设我们能求出这些点以及其出去后把图分为几块之后那几块分别的大小. 是不是发现了什么? 对于非割点,答案显然是2*(n-1) (因为它不能影响别的点对连…
四.Implementation: The Building Blocks 实现:构件 This is the essential part of this guide. We will introduce and explain some explicit rules with examples. You can follow these rules and apply in your solution while implementing the Domain Driven Design.…