Day5 - H - Supermarket POJ - 1456】的更多相关文章

A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of time units starting from the moment the sale begins. Each product takes precisely one unit…
链接: http://poj.org/problem?id=1456 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=82830#problem/G 代码: #include<iostream> #include<cstdio> #include<cmath> #include<algorithm> #include<cstring> #include<cstdlib> us…
A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of time units starting from the moment the sale begins. Each product takes precisely one unit…
#include<iostream> #include<algorithm> using namespace std; const int N=1e5; struct edge{ int w; int deadline; }e[N]; bool cmp(edge a,edge b) { return a.w>b.w; } int f[N]; int find(int x) { if(f[x]!=x) f[x]=find(f[x]); return f[x]; } int ma…
题目大意:n个物品,每个物品有一定的保质期d和一定的利润p,一天只能出售一个物品,问最大利润是多少? 题解:这是一个贪心的题目,有两种做法. 1 首先排序,从大到小排,然后每个物品,按保质期从后往前找,找到第一个没被占用的日期,然后出售. code: #include<cstdio> #include<iostream> #include<cstring> #include<algorithm> using namespace std; typedef lo…
F - Supermarket Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1456 Appoint description:  System Crawler  (2015-11-30) Description A supermarket has a set Prod of products on sale. It earns a p…
Supermarket Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 1456 Description A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx…
题目链接:http://poj.org/problem?id=1456 Time Limit: 2000MS Memory Limit: 65536K Description A supermarket has a set Prod of products on sale. It earns a profit px for each product x∈Prod sold by a deadline dx that is measured as an integral number of tim…
[题目链接] http://poj.org/problem?id=1456 [算法] 贪心 + 堆 [代码] #include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #inc…
题目传送门 传送点I 传送点II 题目大意 有$n$个商品可以销售.每个商品销售会获得一个利润,但也有一个时间限制.每个商品需要1天的时间销售,一天也只能销售一件商品.问最大获利. 考虑将出售每个物品尽量外后安排.这样当一个商品不能安排的时候看能不能替换掉它能够出售的时间中盈利最小的商品. 因此可以将物品排序,这样只用考虑能否让每个物品出售. 为了找到第一个空闲时间,又因为已经安排的时间不会改变,所以用并查集将已经安排了出售的时间段缩起来. Code /** * poj * Problem#14…