E - Power Strings Time Limit:3000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = &…

[题意] 给出一个字符串,求出最小周期. [思路] 对KMP的next数组的理解与运用orz ①证明:如果最小周期不等于它本身,则前缀和后缀必定有交叉. 如果没有交叉,以当前的next[n]为最小周期, 中间部分可能会小于next[n](无解),或者中间可能由若干个前缀组成,此时next[n]会变大,舍去! ----------------------- ----------------------- ②证明:假设满足了n%(n-next[i])==0,那么n-next[i]是周期 这部分证明直…

A character string is said to have period k if it can be formed by concatenating one or more repetitionsof another string of length k. For example, the string ”abcabcabcabc” has period 3, since it is formedby 4 repetitions of the string ”abc”. It als…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 36926   Accepted: 15254 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…

注意,在IDE运行时,可能会因为开的数组太大而报错,这时我们可以把数组开小一点来进行调试....提交的时候把数组的大小改成1000005即可.... #include <iostream> #include <cstdio> #include <cstring> using namespace std; const int maxn = 1000005; int main() { char str[maxn]; while (scanf("%s",…

Time Limit:3000MS Memory Limit:65536KB 64bit IO Format:%I64d & %I64u Submit Status Practice POJ 2406 Appoint description: Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "…

Power Strings   Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 47748   Accepted: 19902 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = &quo…

Power Strings Problem's Link: http://poj.org/problem?id=2406 Mean: 给你一个字符串,让你求这个字符串最多能够被表示成最小循环节重复多少次得到. analyse: KMP之next数组的运用.裸的求最小循环节. Time complexity: O(N) Source code:  ;;      ;);      ) ;}/* */…

题目链接:点击进入 事实上就是KMP算法next数组的简单应用.假设我们设这个字符串的最小周期为x 长度为len,那么由next数组的意义,我们知道len-next[len]的值就会等于x.这就是这个题目的关键点. 代码例如以下: #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int maxn=1000000+100; char str[maxn]; in…

Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 33178   Accepted: 13792 Description Given two strings a and b we define a*b to be their concatenation. For example, if a = "abc" and b = "def" then a*b = "…