Gold Coins Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 21767   Accepted: 13641 Description The king pays his loyal knight in gold coins. On the first day of his service, the knight receives one gold coin. On each of the next two days…

Gold Balanced Lineup Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 13215 Accepted: 3873 Description Farmer John's N cows (1 ≤ N ≤ 100,000) share many similarities. In fact, FJ has been able to narrow down the list of features shared by h…

Pie Time Limit: 5000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 109 Accepted Submission(s): 52   Problem Description My birthday is coming up and traditionally I'm serving pie. Not just one pie, no, I have a…

POJ的题目都是英文的,所以,,,还是直接贴代码吧 #include<stdio.h> int main(){ int x,y,z; int n,nm,max; scanf("%d",&n); while(n--){ int num[60]={0}; scanf("%d",&nm); for(x = 0;x < nm; x++){ scanf( "%d",&y); num[ y+x+1 ]=1; } fo…

set ANSI_NULLS ON set QUOTED_IDENTIFIER ON go -- ============================================= -- Author: *** -- Create date: 2014-03-27 20:00 -- Description: 采用最新的 row_number() over 技术高效分页方法 -- ============================================= ALTER PRO…

DZY Loves Chessboard time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output DZY loves chessboard, and he enjoys playing with it. He has a chessboard of n rows and m columns. Some cells of the ches…

#include <cstdio> #include <iostream> #include <cstring> #include<queue> #include<cmath> using namespace std; const int INF = 0x3fffffff; int g[1005][1005]; int pre[1005]; int m; int bfs(int s,int t) { queue<int>q; q.pu…

说明: (1)日期以年月形式显示:convert(varchar(7),字段名,120) , (2)加一列 (3)自编号: row_number() over(order by 字段名 desc) as RowID row_number() over(partition by 字段1 order by 字段2) as RowID (4)自编号的限制(不可直接在WHERE条件中加) 举例说明: 想要达到的效果:按月统计各工种的前5名(以件数为依据) 初始SQL语句: select sum(Sum_…

(1)Convert 函数 select Convert ( VARCHAR(7),ComeDate,120) as Date ,Count(In_code) as 单数,Sum(SumTrueNum) as 件数 from T_In_Top  where  ComeDate between '2013-01-01' and '2014-08-04' and In_top_State='已完成' and Case_ID=14  and Store_ID=41 group by Convert (…

对链表进行排序,要求时间复杂度为O(n log n) ,不使用额外的空间. 我一开始的想法是借助quicksort的思想,代码如下: # time O(nlog(n)) # Definition for singly-linked list. class ListNode: def __init__(self, x): self.val = x self.next = None class Solution: def sortList(self, head): if head is not No…