N! Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 262144/262144 K (Java/Others)Total Submission(s): 100274 Accepted Submission(s): 30006 Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N! Input One N in…
N! Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 34687 Accepted Submission(s): 9711 Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N! Input One N in one…
B - 2 Time Limit:5000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 1042 Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N! Input One N in one line, process to the end of file. Out…
我们都知道如何计算一个数的阶乘,可是,如果这个数很大呢,该如何计算? 当一个数很大时,利用平常的方法是求不出来它的阶乘的,因为数据超出了范围.因此我们要用数组来求一个大数的阶乘,用数组的每位表示结果的每个位数.话不多说,直接上代码 #include<stdio.h> #include<string.h> int main() { int i,j,n,temp,d=1,carry;//temp为阶乘元素与临时结果的乘积,carry是进位 ,d是位数 int a[3000];//确保数…
N! Time Limit: 10000/5000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 55659 Accepted Submission(s): 15822 Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N! Input One N in on…
传送门:http://acm.hdu.edu.cn/showproblem.php?pid=1018 Big Number Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 42715 Accepted Submission(s): 20844 Problem Description In many applications very…
题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=1042 Problem Description Given an integer N( ≤ N ≤ ), your task is to calculate N! Input One N in one line, process to the end of file. Output For each N, output N! in one line. Sample Input Sample…