题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3605 Escape Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 10349    Accepted Submission(s): 2476 Problem Description 2012 If this is the end of t…

思想:缩点+sap Max,t还可以缩小,优化,高数课写的,有点丑,暂时懒得改. #include<cstdio> #include<cstdlib> #include<iostream> #include<memory.h> #include<algorithm> #include<cstring> #include<cmath> using namespace std; ; const int inf=0x7fffff…

2012 If this is the end of the world how to do? I do not know how. But now scientists have found that some stars, who can live, but some people do not fit to live some of the planet. Now scientists want your help, is to determine what all of people c…

HDU - 3605 : acm.hdu.edu.cn/showproblem.php?pid=3605 题目: 有1e5的的人,小于10个的星球,每个星球都有容量,每个人也有适合的星球和不适合的星球.问所有人是否能住到星球上去. 思路: 这道题目如果直接用常用的建图方式是不行的,因为人太多了,相应的边就很多,会TLE.那要怎么做呢,因为只有十个星球,所以有很多人的特征是相同的,所以把这1e5个点可以缩成最多1024个点.这样建图跑dinic就行了. //#pragma GCC optimize…

[题意]: 有N个人,M个星球,给N*M矩阵,(i, j)为1代表i可以到j星球,0代表不能,问是否能把所有人转移走. [思路]: N的范围为1e6,如果让每个人与星球连边一定TLE,再根据矩阵每一行只有0,1可以进行状压,把相同状态idx的人合并到数组siz[idx], 在扫描状态,与符合条件的星球连边. [建图]: 超级源点sp -> idx  边权siz[idx] idx -> M 边权inf M -> 超级汇点tp 边权为容量 #include <bits/stdc++.h…

Escape Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 13271    Accepted Submission(s): 3351 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=3605 Description: 2012 If this is the end of the world…

HDU 3605 Escape (网络流,最大流,位运算压缩) Description 2012 If this is the end of the world how to do? I do not know how. But now scientists have found that some stars, who can live, but some people do not fit to live some of the planet. Now scientists want you…

Gym 101047E Escape from Ayutthaya Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u  Practice  Description standard input/output Ayutthaya was one of the first kingdoms in Thailand, spanning since its foundation in 1350 to…

一.前言 讲这3个方法区别的文章太多了,但是大部分写的都很绕.本文试图从实践角度去讲这3个方法. 二.escape和它们不是同一类 简单来说,escape是对字符串(string)进行编码(而另外两种是对URL),作用是让它们在所有电脑上可读.编码之后的效果是%XX或者%uXXXX这种形式.其中 ASCII字母.数字.@*/+ ,这几个字符不会被编码,其余的都会.最关键的是,当你需要对URL编码时,请忘记这个方法,这个方法是针对字符串使用的,不适用于URL.事实上,这个方法我还没有在实际工作中用…

public static string Escape(string s) { StringBuilder sb = new StringBuilder(); byte[] ba = System.Text.Encoding.Unicode.GetBytes(s); for (int i = 0; i < ba.Length; i += 2) { if (ba[i + 1] == 0) { //数字,大小写字母,以及"+-*/._"不变 if ( (ba[i] >= 48…