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1054 - Efficient Pseudo Code    PDF (English) Statistics Forum Time Limit: 1 second(s) Memory Limit: 32 MB Sometimes it's quite useful to write pseudo codes for problems. Actually you can write the necessary steps to solve a particular problem. In th…
题目连接: http://www.lightoj.com/volume_showproblem.php?problem=1054 题目大意: 给出n,m,问n^m的所有因子之和是多少? 解题思路: 补充知识: 1:对于一个数字n=p1^t1+p2^t2+p3^t3+.........+pn^tn.求n因子和等价于n所有因子的子集所对应值相加之和—(p1^0+p1^1+p1^2+......+p1^t1)*(p2^0+p2^1+......+p2^t2)*.....*(pn^0+pn^1+....…
题目链接:http://lightoj.com/volume_showproblem.php?problem=1054 题意:给你两个数n和m, 求n^m的所有因子和,结果对1000000007求余;(n和m在int范围内)  和求因子个数有一定的关系,一个数 n 可以表示成 n = p1^a1 * p2^a2 * p3^a3 * ... pk^ak,(其中pi是n的素因子) 那么n的因子和就是 (p1^0+p1^1+p1^2+...+p1^a1)*(p2^0+p2^1+p2^2+...+p2^…
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专题[vjudge] - 数论0.1 web-address : https://cn.vjudge.net/contest/176171 A - Mathematically Hard 题意就是定义一个函数S.其中S(x)=sqr(1~x中与x互质的数的个数). 显然,这里要运用到Euler函数(即φ函数,题后已给出).那么,我们计算出5*10^6以内的phi后,计算一个前缀平方和就行了. B - Ifter Party 题意就是让你求一个数大于L的因数,并把它们升序输出.比较水,但是容易PE…
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